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4 years ago

Solve the compound inequality.negative 5 x less than or equals minus 10

Mathematics

1 answer:

Doss [256]4 years ago

3 0

negative 5 x less than or equals minus 10

-5x<=-10

divide by -5 (this will flip the inequality)

x>=2

Solution: x>=2

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An organization founded by businesses in a specific industry for the purpose of collaboration between companies is called a(n):

Katena32 [7]

Trade association... and next time label this is in the correct subject

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3 years ago

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Please help- A bakery sells cakes for $18 each and pies for $15 each. Last weekend the bakery sold 118 total items and earned $1

Sati [7]

Answer:

64 pies sold

Step-by-step explanation:

x = number of cakes sold

y = number of pies sold

Last weekend the bakery sold 118 total items

x + y = 118

Last weekend the bakery earned $1,932.

18x + 15y = 1,932.

Get rid of one of the terms, in this case x.

x + y = 118 becomes

18x + 18y = 2124

Subtract the equations from each other

(18x - 18x) + (18y - 15y) = 2124 - 1932

3y = 192

y = 64

Subsititue y into the orginal qeuation to solve for x and check it's right.

x + 64 = 118

x = 118 - 64 = 54

18(54) + 15(64) = 1932

4 0

3 years ago

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Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

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1 year ago

Solve the linear equation.

nydimaria [60]

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3 years ago

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What is the equation of the line that passes through the point (2, -1) and has a slope of ?

DENIUS [597]

Answer:

y = 3/2x - 4