Help me with question 7 pls

Mathematics

1 answer:

Marrrta [24]3 years ago

5 0

If the coefficient of x^2 is negative, the graph will be n shaped and curve down instead of like a u shape if it was positive. If the vertex is below the x axis and curves down, it won’t pass the x axis, Tia is right.

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Find the rectangular coordinates of the point with the polar coordinates ordered pair negative 7 comma 5 pi divided by 3.

KiRa [710]

Polar coordinates

$(r, \theta) = (-7, \dfrac{5 \pi}{3})$

We convert to rectangular coordinates using

$(x,y)=(-7 \cos \dfrac{5 \pi}{3} , -7 \sin \dfrac{5 \pi}{3})$

We'll negate the angle (and add two pi) which negates the sine but leaves the cosine alone.

$(x,y)=(-7 \cos \dfrac{\pi}{3}, 7 \sin \dfrac{\pi}{3})$

Of course 60 degrees is the biggest cliche in trig.

$(x,y) = (-7 (\dfrac 1 2), 7( \dfrac{\sqrt{3}}{2}) )$

$(x,y) = (-\dfrac{7}{2}, \dfrac{7\sqrt{3}}{2} )$

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i think this is what u are talking about right

if not im srry i don't now

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