Pattern in 6, 7, 13, 20, ?

While her husband spent 2½ hours picking out new speakers, a statistician decided to determine whether the percent of men who en

AVprozaik [17]

Answer:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

$p_v =P(Z>0.0057)=0.4977$

The p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

Step-by-step explanation:

1) Data given and notation

$X_{M}=23$ represent the number of men that said they enjoyed the activity of Saturday afternoon shopping

$X_{W}=8$ represent the number of women that said they enjoyed the activity of Saturday afternoon shopping

$n_{M}=66$ sample of male selected

$n_{W}=23$ sample of demale selected

$p_{M}=\frac{23}{66}=0.34848$ represent the proportion of men that said they enjoyed the activity of Saturday afternoon shopping

$p_{W}=\frac{8}{23}=0.34782$ represent the proportion of women with red/green color blindness

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to check if the percent of men who enjoy shopping for electronic equipment is higher than the percent of women who enjoy shopping for electronic equipment , the system of hypothesis would be:

Null hypothesis: $p_{M} \leq p_{W}$

Alternative hypothesis: $p_{M} > p_{W}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{W}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{W}})}}$ (1)

Where $\hat p=\frac{X_{M}+X_{W}}{n_{M}+n_{W}}=\frac{23+8}{66+23}=0.34831$

3) Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.34848-0.34782}{\sqrt{0.34831(1-0.34831)(\frac{1}{66}+\frac{1}{23})}}=0.0057$

4) Statistical decision

Using the significance level provided $\alpha=0.05$ , the next step would be calculate the p value for this test.

Since is a one side right tail test the p value would be:

$p_v =P(Z>0.0057)=0.4977$

So the p value is a very high value and using the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the percent of men who enjoy shopping for electronic equipment is NOT significantly higher than the percent of women who enjoy shopping for electronic equipment.

4 0

3 years ago

2^3a^7 times 2a^3 NEEE HELP

hichkok12 [17]

Step-by-step explanation:

explain step by step on photo, double check just in case

6 0

3 years ago

Appreciate the support!

andreyandreev [35.5K]

The volume of a rectangular prism is represented by the following equation:

$V=w*h*l$

Where the variables are for volume, width, height, and length, respectively.

We are given that the area of one end is 16 cm² (units have to be correct when solving these problems, so it's 16 cm², not 16 cm as described in the problem). We know that $A=w*h$

Using this knowledge, we can change the volume equation to our needs.

$V=w*h*l$

$V=(w*h)*l$

$V=A*l$

Note: We know that A is 16 since it's given

$V=16*l$

The volume is 208 cm³ (once again, incorrect units given). Insert this into the equation.

$208=16*l$

Divide both sides of the equation by 16.

$13=l$

The length is 13 cm.

Let me know if you need any clarifications, thanks!

4 0

3 years ago

A doctor is measuring the mean systolic blood pressure of female students at a large college. Systolic blood pressure is known t

Nana76 [90]

Answer:

The correct option is (b).

Step-by-step explanation:

The (1 - α)% confidence interval for population mean (μ) is:

$CI=\bar x\pm z_{\alpha/2}\times\frac{SD}{\sqrt{n}}$

The confidence interval for population mean can be computed using either the z-interval or t-interval.

The t-interval is used if the following conditions are satisfied:

The population standard deviation is not known
The sample size is large enough
The population from which the sample is selected is normally distributed.

For computing a (1 - α)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.n < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.

In this case the sample size is, n = 28 < 30.

Also it is provided that the systolic blood pressure is known to have a skewed distribution.

Since the sample is small and the population is not normally distributed, the sampling distribution of sample mean will not be approximated by the normal distribution.

Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.

The correct option is (b).

5 0

3 years ago

Volume of composite figures

Feliz [49]

✍️Answer: