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2 years ago

What is the equation for the line shown?

Mathematics

1 answer:

bearhunter [10]2 years ago

3 0

Answer:

option B

Step-by-step explanation:

we know that the equation of the line is:

y=mx+b

m= slope= (y2-y1)/(x2-x1)

we have two points given from the graph:

point 1: (0,2)

point 2: (2,-1)

we to find the slope:

m=(-1-2)/(2-0)

m= -3/2= slope

we need to find "b"

using the point (0,2), we have:

2=0x+b

so we have b=2

finally we have

y=(-3/2)x+2 = option B

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maks197457 [2]

To answer this item, we make use of the equation derive from the Pythagorean theorem for right triangles which states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the two shorter sides. If we let x be the measure of both the shorter sides (we call this as legs), we have,
(14 in)² = (x²) + (x²)
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Divide both sides of the equation by 2,
98 in² = x²
To get the value of x, we get the square root of both sides of the equation,
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2 years ago

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Ivan

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Step-by-step explanation:

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3 years ago

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Shane downloaded 5 songs in two minutes At this rate, how many songs can he download in ½ hour?

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Answer:

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There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

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3 years ago