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bearhunter [10]
3 years ago
8

What is the equation for the line shown?

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

option B

Step-by-step explanation:

we know that the equation of the line is:

y=mx+b

m= slope= (y2-y1)/(x2-x1)

we have two points given from the graph:

point 1: (0,2)

point 2: (2,-1)

we to find the slope:

m=(-1-2)/(2-0)

m= -3/2= slope

we need to find "b"

using the point (0,2), we have:

2=0x+b

so we have b=2

finally we have

y=(-3/2)x+2 = option B

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Write in slope intercept form of the equation of a line passing through (-1,4) and perpendicular to y=x-5.
andrew11 [14]

Answer:

y=-x+3

Step-by-step explanation:

The general slope-intercept equation of a line is y=mx+b where m is the slope and b represents the y intercept. y and x are simply a point the line passes through. In this case, y=x-5, meaning m=1 and b=-5.

In order to find the perpendicular slope, we should take the current slope's <u>negative reciprocal</u>. We have:

-\frac{1}{1} =\\-1

Therefore, our perpendicular slope is -1. We now have equation:

y=-x+b

We can plug in the known values of the point (-1,4) to solve for b.

4=(-1)*(-1)+b\\4=1+b\\b=3

If we now put what we found together, we have equation

y=-x+3

<em>I hope this helps! Let me know if you have any further questions :)</em>

7 0
3 years ago
Which statement describes the solution(s) to the system of equations 2 x − 3 y = − 10 and − 6 x + 9 y = − 10 ?
Aleonysh [2.5K]
X = 3/2 or 1 1/2

Both of the equations equal -10, therefor the equations are equal.
3 0
2 years ago
Can someone please do this ill mark brainliest
Svet_ta [14]

Answer:

-60  im pretty sure this is it

                                 

8 0
3 years ago
3x+6=15<br><br> solve for x<br><br> x= ?
mylen [45]

Answer: x=3

Step-by-step explanation: Subtract 6 from both sides, Simplify  

15−6 to 9, and then divide both sides by three.

3x=15−6

3x=9

x=​9/3

x=3

​

Hope this helps, have a BLESSED day! ☺️

5 0
3 years ago
Read 2 more answers
Which equation has the solutions x = startfraction 5 plus-or-minus 2 startroot 7 endroot over 3 endfraction?
Shtirlitz [24]

The equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

<h3>How to determine the equation?</h3>

The solution is given as:

x = \frac{5 \pm \sqrt{7}}{3}

The solution to a quadratic equation is

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

By comparing both equations, we have:

-b = 5

b^2 - 4ac = 7

2a = 3

Solve for b in -b = 5

b = -5

Solve for a in 2a = 3

a = 1.5

Substitute values for a and b in b^2 - 4ac = 7

(-5)^2 - 4 * 1.5c = 7

Evaluate

25 - 6c = 7

Subtract 25 from both sides

-6c = -18

Divide by - 6

c = 3

So, we have:

a = 1.5

b =  -5

c = 3

A quadratic equation is represented as:

ax^2 + bx + c = 0

So, we have:

1.5x^2 - 5x +3 = 0

Multiply through by 2

3x^2 - 10x + 6 = 0

Hence, the equation that has the solution x = \frac{5 \pm \sqrt{7}}{3} is 3x^2 - 10x + 6 = 0

Read more about quadratic equation at:

brainly.com/question/1214333

#SPJ1

7 0
2 years ago
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