8x^4+24x^3-27x-81 what is the polynomial factor?

1 answer:

3 0

$8x^4+24x^3-27x-81=8x^3(x+3)-27(x+3)\\\\=(x+3)(8x^3-27)=(x+3)(2^3x^3-3^3)=(x+3)[(2x)^3-3^3]\\\\\text{use}\ a^3-b^3=(a-b)(a^2+ab+b^2)\\\\=(x+3)(2x-3)[(2x)^2+(2x)(3)+3^2]\\\\=\boxed{(x+3)(2x-3)(4x^2+6x+9)}$

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Simplify 6a+5w-2a+w .....,,.,,.,..,..,,

joja [24]

6a + 5w - 2a + w

Step 1:

Simplify A’s

6a - 2a = 4a

Step 2:

Simplify Ws

5w + w = 6w

Step 3:

Put together

4a + 6w

3 0

3 years ago

A jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30o east of north (or 30o ne). how far is he fro

Natasha_Volkova [10]

Magnitude of the net displacement: 7.0 miles

Step-by-step explanation:

In order to find the total displacement of the man, we have to resolve each displacement along the x- and y- direction.

Taking x as positive x direction and y as positive north direction:

- The first motion is 3 miles due east, so

$A_x = 3 mi\\A_y = 0$

- The second motion is 5 miles at $30^{\circ}$ east of north, so:

$B_x = 5 sin 30^{\circ}=2.5 mi\\B_y = 5 cos 30^{\circ}=4.3 mi$

So the components of the net displacement are

$R_x = A_x + B_x = 3 + 2.5 = 5.5 mi\\R_y = A_y+B_y = 0 + 4.3 = 4.3 mi$

And so the magnitude of the net displacement is

$d=\sqrt{R_x^2+R_y^2}=\sqrt{5.5^2+4.3^2}=7.0 mi$

So, he is 7.0 miles far from the house.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

4 0

3 years ago

PLEASE HELP ASAP!!!!!

mojhsa [17]

Answer:

C. 336 ways

Step-by-step explanation:

Plz mark as brainliest! :D

8 0

3 years ago

I need help with #5

chubhunter [2.5K]

Wouldn't this be in literature?

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3 years ago

9. The ticket at right has a perimeter of 42 cm.

Liula [17]

Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.