Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,
P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216.
P(three 5s) = (1 x 1 x 1)/216 = 1/216
P(one 5 or two 5s) = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36
Answer:
k=-8.
Step-by-step explanation:
Step 1: subtract 14 from both sides from "2.25k - 20 =6.5k +14"
Step 2: Subtract 2.25k from both sides from "2.25k-34=6.5k
Step 3: Divide both sides by 4.25 from -34=4.25x
Your answer is k= -8.
It says -8=k.
Answer:
Number of students in the science club are 38.
Step-by-step explanation:
Let, the number of students in the robotics club = x and the number of students in the science club = y.
Since, there are total 82 students in both the clubs.
So, we have,
.
Moreover, the number of students in the science club are 6 less than those in the robotics club.
So, we get,
![y=x-6](https://tex.z-dn.net/?f=y%3Dx-6)
Thus, solving the system of equations, we get,
implies
implies
i.e. 2x= 88 i.e. x= 44
So,
implies y= 44-6 i.e. y= 38
Hence, the number of students in the robotics club are 44 and the science club are 38.
Original: 11.3 feet by 14.3 feet
new: 14.7 feet by 18.6 feet
Well, it depends. We will need some other days and temps to help you.