Answer:
Level of operation
Explanation:
The operating system is the system that enables other software to run on a device. It therefore handles the data between the user and the different features of the hardware, such as hosting device drivers. It also determines the core language used on the device, such as Windows, apple or Linux. This provides conformity accross devices allowing software and hardware companies to produce compatible products.
Answer:
3e : 00111110 (62)
3e0 : 0000001111100000 (992)
3e00 : 0011111000000000 (15872)
Explanation:
Converting the given hexadecimal numbers to binary and decimal format:
1) 3e
3-> 0011
e-> 1110
Combining , 3e -> 00111110
This can be converted to decimal by multiplying each 1 in the binary representation by 2^(position -1) and adding the results.
So 3e = 32+16+8+4+2 = 62
2) 3e0
Binary => 0000001111100000
Converting to decimal : 992 [ This is 16 times a]
3) 3e00
Binary => 0011111000000000
Converting to decimal : 15872 [ This is 16 times b]
So adding a 0 to the hex representation multiplies the decimal number by 16.
Answer:
With drag-and-drop editing, word automatically displays a paste options button near the pasted or moved text.
Explanation:
<u>Option A:</u> Cut and paste option is invalid because, cut and paste option does not provide paste symbol near the copied text. This option and cut and paste a selected text.
<u> Option C :</u> Inline is invalid in this context
<u>Option D: </u>Copy and Carry is not valid because the option “copy” is available where as carry is not available.
<u>Option B:</u> Drag and drop is the right answer because, it provides paste option by using this feature. A text can be drag and drop by selecting the text and dragging the mouse with the left click
The most common way I've seen is to have a slide where you have the additional information. It can be phone numbers, email address, websites, books, anything you want to refer to.
People tend to photograph these slides so make sure the information is error free and that you add you own marketing info to the slide as well.
Answer:
Part a: The program will print 3.
Part b: The program will print 4
Part c: The program will print 1.
Explanation:
Part a: As the scoping is static, the x integer has a value of 1 and the y integer has a value of 2 so the addition is 2+1=3.
Part b: As the scoping is dynamic with deep binding, the x integer has a value of 2 and the y integer has a value of 2 so the addition is 2+2=4.
Part c: As the scoping is dynamic with shallow binding, the x integer has a value of 1 so it will print 1.
