Answer:
yes, that would be an isosceles triangle
Correct question:
An urn contains 3 red and 7 black balls. Players A and B withdraw balls from the urn consecutively until a red ball is selected. Find the probability that A selects the red ball. (A draws the first ball, then B, and so on. There is no replacement of the balls drawn).
Answer:
The probability that A selects the red ball is 58.33 %
Step-by-step explanation:
A selects the red ball if the first red ball is drawn 1st, 3rd, 5th or 7th
1st selection: 9C2
3rd selection: 7C2
5th selection: 5C2
7th selection: 3C2
9C2 = (9!) / (7!2!) = 36
7C2 = (7!) / (5!2!) = 21
5C2 = (5!) / (3!2!) = 10
3C2 = (3!) / (2!) = 3
sum of all the possible events = 36 + 21 + 10 + 3 = 70
Total possible outcome of selecting the red ball = 10C3
10C3 = (10!) / (7!3!)
= 120
The probability that A selects the red ball is sum of all the possible events divided by the total possible outcome.
P( A selects the red ball) = 70 / 120
= 0.5833
= 58.33 %
Take a look at one of the triangles. Base is 10 ft and height is sqrt(10^2-5^2), or h = sqrt(75) = 5sqrt(3).
Then the area of one such triangle is A = (1/2)(base)(height)
= (1/2)(10)(3sqrt(3) ).
Since there are 2 such triangles, mult. this result by 2: We get
30sqrt(3).
This leaves us with the task of finding the area of the slant sides and of the base. Base = 150 ft^2; 2 slant sides = 2(150 ft^2) = 300 ft^2. Total 450 ft^2.
Now please evaluate 30sqrt(3)+450 ft^2.
2x squared +1 (-)x squared -7 is
a.) x squared +8