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EastWind [94]
4 years ago
6

Your bike lock has 3 digits numbered 0 through

Mathematics
1 answer:
KATRIN_1 [288]4 years ago
8 0
I think the answer is 81
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Using a calculator, evaluate the cosine of 18* to the hundredths decimal place: A. 0.951 B. 0.95 C. 0.66 D. 0.660
Alona [7]

Answer:

Option B

Step-by-step explanation:

=> Cos 18

=> 0.9510

<u><em>To the hundredths place</em></u>

=> 0.95

7 0
3 years ago
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Why does a table with 3 legs not rock geometry question
hodyreva [135]
I'm assuming the table is triangle shaped, therefore has a leg on each end, and doesn't rock. or it could be circular and have 3 legs and not rock...

hope this helped :)
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3 years ago
3y+4y+6=20 solve variable. include steps, also check your answer!
stira [4]

Answer:2

Step-by-step explanation:

3y+4y+6=20

7y+6=20

7y=20-6=14

Y=14/7=2

6+8+6=20

8 0
3 years ago
(PLEASE HELP ASAP) Marc mixes blue and yellow paint to make his favorite shade of green, which he'll use to paint his house. He
azamat
He can use 14 cans of blue and 20 cans of yellow because blue goes up by 2 and yellow goes up by 3 each time hope this helped (mark brainliest?)
6 0
2 years ago
Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to
Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4).  You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

3^2+y^2=25

9+y^2=25

Subtract 9 on both sides:

y^2=25-9

y^2=16

Take the square root of both sides:

y=\pm \sqrt{16}

y=\pm 4.

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

(\pm 5)^2+y^2=25

25+y^2=25

Subtract 25 on both sides:

y^2=25-25

Simplify:

y^2=0

There is only one value y such that when you square it gives you 0. That is 0.

x=5 only gives y=0 and x=-5 only gives y=0.

There is no circle, unless it is a circle with radius 0 which means it really wouldn't be a circle, that is a function.

8 0
3 years ago
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