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dalvyx [7]
3 years ago
10

- a. Find three pairs of numbers for which the least common multiple

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

Step-by-step explanation:

74939e+1364

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The point A(4, 1) is reflected over the point (0, -3) and its image is point B. What are the coordinates of point B?
omeli [17]

A reflection over the point (0,0) is given by:

(x,y)\rightarrow(-x,-y)

Nevertheless, the reflection is being made over the point (0,-3). We can first make a traslation of the point (0,-3) to the origin. Then, reflect the new coordinates of the point A through the origin and then bring back the new origin to (0,-3).

First, make a traslation such that the new coordinates of (0,-3) are (0,0):

(x,y)\rightarrow(x,y+3)

Then, apply a reflection through the origin:

(x,y+3)\rightarrow(-x,-y-3)

Finally, make a traslation reciprocal to the first one:

(-x,-y-3)\rightarrow(-x,-y-3-3)=(-x,-y-6)

Therefore, the reflection over the point (0,-3) can be written as:

(x,y)\rightarrow(-x,-y-6)

Substitute (x,y)=(4,1) to find out the new coordinates of A after the reflection:

\begin{gathered} A\rightarrow B \\ \Rightarrow(4,1)\rightarrow(-4,-1-6)=(-4,-7) \end{gathered}

Therefore, the coordinates of the point B are (-4,-7).

4 0
1 year ago
Find the median of the data in the dot plot below. points Quiz score for each student in Mrs. Baker's class 1 0 1 2 3 4 5 6 6 7
irga5000 [103]

Answer: 5

Step-by-step explanation: The answer is 5 since "median" means the middle. If you count the numbers you get 13. Since 13 isnt even you count half of 12 which is 6 then count 6 on both sides, youll end up with 5 not fitting into the group. Im not the best at explaining so im sorry! Hope this helps!  

5 0
3 years ago
Read 2 more answers
PLEASE HELPPPPPPPP To get brainiest
jeka94

Answer:

C

Step-by-step explanation:

7 0
3 years ago
What is the probability that she chose the four students so that exactly ONE of them is a junior?
8090 [49]

Answer:

  B)  0.246

Step-by-step explanation:

The desired probability is the sum of the probabilities of each of the ways one junior can be chosen. If we let a, b, c, d represent the ratio of juniors in classes 1 to 4, then this probability is ...

  p(1 junior) = (a)(1-b)(1-c)(1-d) + (1-a)(b)(1-c)(1-d) + (1-a)(1-b)(c)(1-d) + (1-a)(1-b)(1-c)(1-d)

We can simplify this a little bit to ...

  p(1 junior) = (1-a)(1-b)(1-c)(1-d) × (a/(1-a) +b/(1-b) +c/(1-c) +d/(1-d))

___

So, for {a, b, c, d} = {9/15, 12/15, 6/15, 3/15} = {3/5, 4/5, 2/5, 1/5} the probability of interest is ...

  p(1 junior) = (2/5·1/5·3/5·4/5) × (3/2 + 4/1 + 2/3 + 1/4) = 24/625 × 77/12

  p(1 junior) = 154/625 ≈ 0.246

_____

<em>Comment on the sum we're computing</em>

Each of the probabilities in the first sum above is ...

  p(junior in given class) · p(not a junior in the other 3 classes)

3 0
3 years ago
Which is an equivalent fraction for .265 ?<br> How do I write 265 in a fraction
andriy [413]

see photo for answer and steps

3 0
3 years ago
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