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3 years ago

2 log x + log 11 WILL MARK BRAINLIEST

Mathematics

1 answer:

tester [92]3 years ago

3 0

Answer:

$log(11 {x}^{2} )$

Step-by-step explanation:

$2logx + log11 \\ \\ = log {x}^{2} + log11 \\ \\ = log( {x}^{2} \times 11) \\ \\ = log(11 {x}^{2} )$

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Sidawidnianddinhwidnaindianwdawdawd

masha68 [24]

Answer:

yes

Step-by-step explanation:

yes

4 0

4 years ago

64^-x+52=128^x<br><br>Please help!

creativ13 [48]

Answer:

x = 23.999996

Step-by-step explanation:

Let's solve your equation step-by-step.

64−x+52=128x

Solve Exponent.

64−x+52=128x

log(64−x+52)=log(128x)(Take log of both sides)

(−x+52)*(log(64))=x*(log(128))

−x+52=(

log(128)

log(64)

)*(x)

−x+52=1.166667*x

−x+52=1.166667x(Simplify both sides of the equation)

−x+52−1.166667x=1.166667x−1.166667x(Subtract 1.166667x from both sides)

−2.166667x+52=0

−2.166667x+52−52=0−52(Subtract 52 from both sides)

−2.166667x=−52

−2.166667x

−2.166667

−52

−2.166667

(Divide both sides by -2.166667)

x=23.999996

Sorry is this is wrong, did it in a hurry :(

6 0

4 years ago

In a group of 100 adults, 70 say they are most likely to do spring houseclean-ing in March, April, or May. Of these 70, the numb

son4ous [18]

Answer:

Adults that clean in March = 18

Adults that clean in April = 48

Adults that clean in May = 4

Step-by-step explanation:

Adults that clean in the months of March, April and May = 70

Let a represent March, b represent April and c represent May.

Therefore, a + b + c = 70 (i)

From the question, the number of adults that clean in April is 14 more than number of the adults cleaning in months of March and May combined.

b - ( a + c) = 14 (ii)

also, the total number who clean in April and May is 2 more than three times the number who clean in March.

b + c - 3a = 2 (iii)

From (i), a + c = 70 - b (iv)

Substituting (iv) into (ii), b - ( 70 - b) = 14

b -70 + b = 14

2b = 84, b =48

Therefore a + c = 70 - 48

a + c = 22; c = 22 - a (v)

Substituting (v) and b = 48 into (iii)

48 + 22 - a -3a = 2

4a = 72, a = 18

Therefore, c = 22 - 18

c = 4

8 0

3 years ago

3 out of every 5 students in Mrs. Wilson's class have brown eyes. There are 20 students in Mrs. Wilson's class. How many of the

Alex787 [66]

Answer:

Step-by-step explanation:

So there is 3:5 right, so 20 divided by 5 equals 4, there are four 5's in 20. Then 4 multiplied by 3 equals 12. So there are 12 students that has BROWN EYES.

<em>Hope I Helped You :)</em>

7 0

2 years ago

Use the disk method or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs

JulsSmile [24]

Answer:

1) V = 12 π ㏑ 3

2) $\mathbf{V = \dfrac{328 \pi}{9}}$

Step-by-step explanation:

Given that:

the graphs of the equations about each given line is:

$y = \dfrac{6}{x^2}, y =0 , x=1 , x=3$

Using Shell method to determine the required volume,

where;

shell radius = x; &

height of the shell = $\dfrac{6}{x^2}$

∴

Volume V = $\int ^b_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx$

$V = \int ^3_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx$

$V = 12 \pi \int ^3_{x-1} \dfrac{1}{x} \ dx$

$V = 12 \pi ( In \ x ) ^3_{x-1}$

V = 12 π ( ㏑ 3 - ㏑ 1)

V = 12 π ( ㏑ 3 - 0)

V = 12 π ㏑ 3

2) Find the line y=6

Using the disk method here;

where,

Inner radius $r(x) = 6 - \dfrac{6}{x^2}$

outer radius R(x) = 6

Thus, the volume of the solid is as follows:

$V = \int ^3_{x-1} \begin {bmatrix} \pi (6)^2 - \pi ( 6 - \dfrac{6}{x^2})^2 \end {bmatrix} \ dx$

$V = \pi (6)^2 \int ^3_{x-1} \begin {bmatrix} 1 - \pi ( 1 - \dfrac{1}{x^2})^2 \end {bmatrix} \ dx$

$V = 36 \pi \int ^3_{x-1} \begin {bmatrix} 1 - ( 1 + \dfrac{1}{x^4}- \dfrac{2}{x^2}) \end {bmatrix} \ dx$

$V = 36 \pi \int ^3_{x-1} \begin {bmatrix} - \dfrac{1}{x^4}+ \dfrac{2}{x^2} \end {bmatrix} \ dx$

$V = 36 \pi \int ^3_{x-1} \begin {bmatrix} {-x^{-4}}+ 2x^{-2} \end {bmatrix} \ dx$

Recall that:

$\int x^n dx = \dfrac{x^n +1}{n+1}$

Then:

$V = 36 \pi ( -\dfrac{x^{-3}}{-3}+ \dfrac{2x^{-1}}{-1})^3_{x-1}$

$V = 36 \pi ( \dfrac{1}{3x^3}- \dfrac{2}{x})^3_{x-1}$

$V = 36 \pi \begin {bmatrix} ( \dfrac{1}{3(3)^3}- \dfrac{2}{3}) - ( \dfrac{1}{3(1)^3}- \dfrac{2}{1}) \end {bmatrix}$

$V = 36 \pi (\dfrac{82}{81})$

$\mathbf{V = \dfrac{328 \pi}{9}}$

The graph of equation for 1 and 2 is also attached in the file below.

5 0

4 years ago