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andrew-mc [135]
3 years ago
5

The length of a rectangle is 3 units shorter than one-third of the width, x. Enter an expression in the box that represents the

perimeter of the rectangle. Note: Use one variable and a fraction in the answer.
Help please! I have absolutely no idea how to solve!!!! ^^^
Mathematics
2 answers:
cluponka [151]3 years ago
7 0
Since length is 3 less than 1/3 width, set up equation l=(1/3)w-3. Because P=2(l+w), substitute l with the euation and get P=2(4/3w-3)
Rashid [163]3 years ago
7 0

Let

y----------> the length side of the rectangle

x-----------> the width side of the rectangle

we know that

the perimeter of the rectangle is equal to

P=2x+2y --------> equation 1

y=\frac{x}{3}-3 --------> equation 2

substitute equation 2 in equation 1

P=2x+2[\frac{x}{3}-3]\\ \\P=2x+ \frac{2x}{3}-6 \\ \\P=(\frac{8x}{3}-6)\ units

therefore

<u>the answer is</u>

P=(\frac{8x}{3}-6)\ units

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Read 2 more answers
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
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