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Alik [6]
3 years ago
10

Which statement is true?

Mathematics
2 answers:
ch4aika [34]3 years ago
6 0
I believe C is correct, 
Also, did you finish the equation for letter D?
Vanyuwa [196]3 years ago
3 0
Yes same I believe c is correct
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If you know the answer to this question please help!! ASAP<br> 7th grade Math
serious [3.7K]

Answer:

22°

Step-by-step explanation:

a right angle have 90°

So

x+68°=90°

=>x=90-68

=22°

3 0
3 years ago
Nathan brings cupcakes to school and gives them to his five best friends, who share them equally. If c represents the number of
tatiyna

Answer: \dfrac{c}{5}

Step-by-step explanation:

Given : Nathan brings cupcakes to school and gives them to his five best friends, who share them equally.

i.e. Number of friends = 5

If c represents the number of cupcakes Nathan brings to school, then the number of cupcakes each of his friends receive is given by using division operation :_

c\div 5=\dfrac{c}{5}

Hence, the expression to show how many cupcakes each of his friends receive. : \dfrac{c}{5}

3 0
3 years ago
Pls help!!!! Cmon I need help!
umka21 [38]

Answer:

A) 0.39

Step-by-step explanation:

A=\pir²=0.38925589615

6 0
3 years ago
Complete the table!!!!
Nookie1986 [14]
1:30 
hope it helps
............................
5 0
4 years ago
Ten pounds of mixed birdseed sells for 8.24 per pound. The mixture is obtained from two kinds of birdseed, with one variety pric
Kipish [7]

Answer:

2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

Explanation:

Given:

Ten pounds of mixed birdseed sells for 8.24 per pound.  

Price of the 1st variety of birdseed=5.68 per pound

Price of the 2nd variety of the birdseed=8.88 per pound.  

To find :

Pounds of 1st variety of birdseed are used in the mixture=?

Pounds of 2ndvariety of birdseed are used in the mixture=?

Solution:

Let the weight of 1st kind added in mixture be n pounds.

Then weight of 2nd kind will be 10 – n pounds.

Now, total cost of mixture = cost of 1st kind birdseed + cost of 2nd kind birdseed

Weight of mixture x cost per pound = weight of 1st kind x cost per pound + weight of 2nd kind x cost per pound.

Substituting the values,

10\times8.24 = n\times5.68 + (10-n)\times8.88

82.4 = 5.68n + 88.8 – 8.88n  

8.88n – 5.68n = 88.8 – 82.4  

3.2n = 6.4  

n = \frac{3.2}{6.4}

n = 2

Then, weight of 2nd kind is 10 – 2 = 8 pounds.

Hence, 2 pounds of 1st kind and 8 pounds of 2nd kind are mixed.

5 0
3 years ago
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