Answer:
This is a perfect cube.
The side length is 4.
Taking the cube root of the volume will determine the side length.
Step-by-step explanation:
We are told that:
A cube has volume 64 centimeters cubed.
The formula for the volume of a cube = s³
Where s = side length
Hence
64 cm³ = s³
We can find s by finding the cube root of both sides
Hence,
cube root(64) = cube root(s³)
s = 4 cm
Note that 64 is a perfect cube because 4 × 4 × 4 = 4³ = 64 cm³
Therefore, it can be concluded of the cube that:
This is a perfect cube.
The side length is 4.
Taking the cube root of the volume will determine the side length.
The answer is A: 4. This is easy once you know the order of operations, aka PEMDAS. Parentheses, exponents, multiplication/division, and addition/subtraction.
Answer:
a) π
b) 33.4
Step-by-step explanation:
C = πd
1) substitute 105 for C: 105 = πd
2) plug in approximate value of 3.14 for π: 105 = (3.14) d
3) isolate to solve for d: 105/3.14 = d
4) simplify: 105/3.14 ≈ 33.4
Answer:
Step-by-step explanation:
Given
Required
Determine E(119.5)
Simply substitute 119.5 for t
Evaluate the expressions in bracket
Solve 0.5²
Hence;
This is not a polynomial equation unless one of those is squared. As it stands x=-.833. If you can tell me which is squared I can help solve the polynomial.
Ok, that is usually notated as x^3 to be clear. I'll solve it now.
x^3-13x-12=0
Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1
Then you have x^2-x-12 now you complete the square.
Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:
The x-term coefficient = −1
The half of the x-term coefficient = −1/2
After squaring we have (−1/2)2=1/4
When we add 1/4 to both sides we have:
x2−x+1/4=12+1/4
STEP 3: Simplify right side
x2−x+1/4=49/4
STEP 4: Write the perfect square on the left.
<span>(x−1/2)2=<span>49/4
</span></span>
STEP 5: Take the square root of both sides.
x−1/2=±√49/4
STEP 6: Solve for x.
<span>x=1/2±</span>√49/4
that is,
<span>x1=−3</span>
<span>x2=4</span>
<span>and the one from before </span>
<span>x=-1</span>
