Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer: Y=-5
Step-by-step explanation:
The reason is because if you look down the y axis from the origin you can see the location where the line crosses over the y axis in this case it was at (0,-5)
See picture for solution steps and answer.
*the table being referred to is attached below
Answer:
The table does not show a proportional relationship between variable g and h.
Step-by-step explanation:
For a proportional relationship to exist between two variables, there must be a constant, of which serves like a unit rate, when comparing two variables.
Thus, in the table attached below, there is no obvious constant of proportionality between variable g and variable h.
Thus,
≠
≠ 
<h3>
Answer: Choice B</h3>
Angle 1 = 147 degrees
Angle 2 = 80 degrees
Angle 3 = 148 degrees
======================================================
Work Shown:
(angle 1) + 33 = 180
angle 1 = 180-33
angle 1 = 147 degrees
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Focus on the left most triangle that has angles 33 and 47 as interior angles. The missing angle is 180-33-47 = 100 degrees
The angle exterior to this 100 degree angle is angle 2
angle 2 = 180-100 = 80
We have enough info to conclude the answer must be choice B.
---------------
Let's keep going to find angle 3
The vertical angle for the 100 degree angle is also 100 degrees. This second 100 degree angle is part of the triangle on the right
This triangle on the right has interior angles 100 and 48
The missing interior angle is 180-100-48 = 32
The angle supplementary to this is 180-32 = 148, which is angle 3.