Answer:
we need to prove : for every integer n>1, the number 
is a multiple of 5.
1) check divisibility for n=1, 
(divisible)
2) Assume that 
is divisible by 5, 
3) Induction,
Now, 
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between 
and is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
0.300 + .020 + 0.006 would be 0.326 in expanded form.
Oh wait a minute i have to write this down
It would be 9/6 which simplifies to 3/2
Answer:
D) cot(C) = 1/2.
Step-by-step explanation:
We can go through each choice and examine is validity.
Choice A)
We have:
Recall that secant is the ratio of the hypotenuse to the adjacent.
With respect to B, the adjacent is 6 and the hypotenuse is 7.
Therefore, sec(B) should be 7/6 instead.
A is incorrect.
Choice B)
We have:
Cotangent is the ratio of the adjacent side to the opposite.
With respect to B, the adjacent side is 6 and the opposite side is 3.
Therefore, cot(B) = 6/3 = 2.
B is incorrect.
Choice C)
C is incorrect for the reasons listed in A.
Choice D)
We have:
Again, cotangent is the ratio of the adjacent side to the opposite.
With respect to C, the adjacent side is 3 and the opposite side is 6.
So, cot(C) = 3/6 = 1/2.
Therefore, D is the correct choice!
