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3 years ago

Solve x = 0.6x + 384

Mathematics

2 answers:

Gelneren [198K]3 years ago

8 0

X = 0.6x + 384 |subtract 0.6x from both sides

0.4x = 384 |divide both sides by 0.4

x = 960

liraira [26]3 years ago

4 0

Answer: The required solution is x = 960.

Step-by-step explanation: We are given to solve the following equation :

$x=0.6x+384~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To solve the given equation, we must take the terms involving unknown variable x on one side.

The solution of equation (i) is as follows :

$x=0.6x+384\\\\\Rightarrow x-0.6x=384\\\\\Rightarrow 0.4x=384\\\\\Rightarrow x=\dfrac{384}{0.4}\\\\\Rightarrow x=960.$

Thus, the required solution is x = 960.

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En ampliar o reducir una fotografía, obtenemos copias de la fotografía original, pero de medida diferente. Si la anchura del ori

antoniya [11.8K]

Answer:

La anchura será de:

6 cm

Step-by-step explanation:

El formato original corresponde al 100%

Si se reduce un 60% quiere decir que:

100 - 60 = 40%

la reducción queda al 40%

entonces, por regla de tres:

15cm es al 100%

A cm es al 40%

A = 15*40/100

A = 6cm

7 0

2 years ago

A school administrator will assign each student in a group of n students to one of m classrooms. If 3 < m < 13 < n, is

tatiyna

Answer:

Hence to get same number of students in each classroom,the sufficient condition is that assign 13n students to each classroom.

Step-by-step explanation:

Given:

There are m classrooms and n be the students

3<m<13<n.

To Find:

Whether it is possible to assign each of n students to one of m classrooms with same no.of students.

Solution:

This problem is related to p/q form has to be integer in order to get same no of students assigned to the classroom.

As similar as ,n/m ratio

So 1st condition is that,

If it is possible to assign the n/m must be integer and n should be multiple of m,

when we assign 3n students to m classrooms ,we cannot say that 3n/m= integer so that n is greater than 13 i.e n=14 and m=6

hence they are not multiple of each other so they will not make same students in each classrooms.

Otherwise,n=14 and m=7 they will give same number but this condition is not sufficient condition to assign the student.

So 2nd condition is that ,

When we assign 13n students to m classrooms, as 13 is prime number and

3<m<13 which implies the 13n/m to be integer so n and m must be multiple of each other.

Suppose n=20 and m=5 classrooms

then 13*20=260 ,

260/5=52 students in each classroom,

4 0

3 years ago

Does 30,40,45 make a right triangle?

zavuch27 [327]

I believe that it does.

8 0

3 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

A=152

7 0

3 years ago

Can i have some help

SVETLANKA909090 [29]

Answer:

b. m = 2, b = 4

Step-by-step explanation:

y = mx + b

m = slope and b = y-intercept

The slope is 2 cause it's going up 2 squares while only going to the right one square each time, so u could right 2/1 but it's not necessary so just 2. And the intercept is 4 because that's where the line intercepts the y-axis.

8 0

2 years ago