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3 years ago

Find the area of triangle ABC when b= 141 degrees a= 7 and c=8

1 answer:

7 0

You basically use the formula height*base/2 to find the area of the triangle. For instance, let's say a is your chosen base, which has a length of 7. You then use the pythagorean theorem of the right triangle (which is formed by splitting the triangle in half), which is a^2+b^2=c^2, and you substitute half your base for a and the other length (8) for c, which is the hypotenuse of the triangle. Note how this is all being done to find "b", which is the height of the triangle, which will then help you substitute all of your known values into the area formula of a triangle to answer your question. I'm not sure if b=141 degrees would have an impact on this question, but I hope this helped you in some way.

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2 years ago

An exterior angle of a triangle equals _______ minus the adjacent interior angle.

insens350 [35]

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5 0

3 years ago

Read 2 more answers

The point (4, –3) is on the terminal side of an angle in standard position. Determine the value of r, and the exact value of sin

viva [34]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

A (4 , -3)

r = ?

sin = ?

cos = ?

tan = ?

Process

1.- Plot the point

This point is in the fourth quadrangle

2.- Calculate r

We have the Opposite side and the Adjacent side

tan Ф = -3/4

tan⁻¹ Ф = Ф = 323.1

Ф = 323.1°

3.- sinФ =

Calculate the hypotenuse

c² = 4² + (-3)²

c² = 16 + 9

c² = 25

c = 5

sinФ = -3/5

cos Ф = 4/5

tan Ф = -3/4

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3 years ago

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cupoosta [38]

Answer:

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Step-by-step explanation:

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2 years ago

HELP plS! if sin 0=7/25, find cos0.

kodGreya [7K]

Hey there! :)

Answer:

csc θ = 25/7.

Step-by-step explanation:

Recall that csc, or cosecant, is the reciprocal of sine. Therefore:

If sin θ = 7/25:

Find the reciprocal:

7/25 --> 25/7.

csc θ = 25/7.

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3 years ago

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