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UNO [17]
1 year ago
9

A number plus 15 exceeds twice that number by 3Translate into algebraic equation ​

Mathematics
1 answer:
bekas [8.4K]1 year ago
3 0

Answer:

n + 15 > (2n) / 3

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Please help me to fill in the blanks
Alja [10]
Oooooo child i wish i could help
5 0
3 years ago
Ms. Potts washed 1/4 of her laundry. Her son washed 3/7 of it. Who washed most of the laundry? How much of the laundry still nee
LenaWriter [7]

Answer:

  • Son washed more
  • Remaining 9/28 of the laundry

Step-by-step explanation:

<u>Make denominators common to see the difference in fractions:</u>

  • 1/4 = 7/28
  • 3/7 = 12/28

Son washed more laundry as 12/28 > 7/28

<u>Together they washed:</u>

  • 7/28 + 12/28 = 19/28 of the laundry

<u>Remaining part is:</u>

  • 1 - 19/28 =
  • 28/28 - 19/28 =
  • 9/28 of the laundry
7 0
3 years ago
Read 2 more answers
First and Second Street are parallel to each other.
garik1379 [7]
If I did this right, it should be:

1. 130 degrees
2. 50 degrees
3. 130 degrees
4. 50 degrees

Here's hoping I'm right. lol
3 0
3 years ago
A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
Natali [406]

Options

The circle at the new location has _____________ the original circle.

- the same center as

- twice the circumference of

- half the radius of

- the same area as

Answer:

the same area as

Step-by-step explanation:

When a circle is translated and reflected, the center of the circle will change; however, its area, circumference, radius and diameter remain the same.

This is so because, translation and reflection only affect the positioning of the circle not the size.

Considering the above analysis, we can conclude that option d answers the question correctly.

8 0
3 years ago
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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