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4 years ago

7

What is the equilibrium constant expression for dissolving calcium carbonate in water?

1 answer:

Over [174]4 years ago

6 0

Equation for dissolving calcium carbonate in water:
<span>CaCO3(s) </span>⇄ Ca²⁺(aq) + CO₃²⁻(aq).
The equilibrium constant expression for this reaction: K = [Ca²⁺] [CO₃²⁻] / [CaCO3(s)], but concentration of CaCO3(s) is 1 (for all solid), so <span>the simpler expression for the equilibrium </span>constant is:K = [Ca²⁺] [CO₃²⁻].

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If you have 3 moles of FeCl3, how many moles of MgCl2 can be produced? FeCl3 + Mg --> MgCl2 + Fe

oksian1 [2.3K]

Answer: 154.09 g

Explanation:

3 Mg + 2 FeCl3 = 3 MgCl2 + 2 Fe

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3 years ago

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Answer:

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pentagon [3]

Answer:

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Explanation:

$HCl (aq) + NaOH (aq) \rightarrow H_2O (l) + NaCl (aq)$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

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Putting values in above equation, we get:

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$M_1=\frac{1\times 2.0 M\times 25 mL}{1\times 50.0 mL}=1.0M$

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3 years ago