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Marta_Voda [28]
2 years ago
9

Which combination of reactants will produce ethyl 3-phenyl-3-oxopropanoate when treated first with an alkoxide and then with a d

iluted aqueous acid?
Chemistry
1 answer:
Nezavi [6.7K]2 years ago
6 0

Ethyl acetate and methyl benzoate combination of reactants will produce ethyl 3-phenyl-3-oxopropanoate when treated first with an alkoxide and then with a diluted aqueous acid

<h3>Ethyl acetate</h3>

One of the most straightforward carboxylate esters is ethyl acetate. The simplest is methyl formate, a former Molecule of the Week. Most people enjoy the taste and aroma of the colorless liquid's sweet, fruity scent.

Ethyl acetate was initially created by combining ethanol and acetic acid, as one might anticipate. The process was the traditional Fischer esterification, which dates back to 1895 and is catalyzed by an acid. This commercial synthesis is still the most popular. A different approach is the Tishchenko reaction, in which acetaldehyde disproportionately reacts with base to form alcohol and acid, which subsequently esterify naturally.

Learn more about Ethyl acetate here:

brainly.com/question/13386859

#SPJ4

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the student ate the pie chart

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You are trying to boil water while camping in the Colorado Rockies. The surrounding barometric pressure is 0.9 bar, and the wate
irga5000 [103]

Answer:

Perfectly Specified

Explanation:

Pressure, P = 0.9 atm

Boiling point = T

Number of components C = 1

Number of phases P = 2

Using  Gibbs phase rule as:

F = C - P + 2

F = 1 - 2 + 2 = 1

At Pressure = 0.9 atm, boiling point is T which means that the temperature is also fixed which is equal to 96.7 °C . The data taken from steam table.

In given problem, the pressure is fixed so temperature is also fixed.

The system is perfectly specified.

8 0
4 years ago
Given the reaction below which of the following best describes the energy changes in this reaction?
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Answer:

first choice

Explanation:

energy is written on the left side is its absorbed

2 elements came together so bonds are formed.

8 0
3 years ago
Help please! A gas occupies 500 mL at 270 mm Hg and 55°C. If the pressure is changed to 1.8 atm and the temperature is
NNADVOKAT [17]

Answer:

V₂ = 112.14 mL

Explanation:

Given data:

Initial volume = 500 mL

Initial pressure = 270 mmHg (270/760 =0.355 atm)

Initial temperature = 55 °C (55 +273 = 328 K)

Final temperature = 100°C (100+273 = 373 K)

Final volume = ?

Final pressure = 1.8 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 0.355 atm × 500mL × 373 K / 328 K × 1.8 atm

V₂ = 66207.5 atm .mL. K /  590.4 K.atm

V₂ = 112.14 mL

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4 years ago
Under the same conditions of temperature and pressure how does a liquid differ from a gas
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Under the same conditions of temperature and pressure, a liquid differs from a gas because the particles of the liquid a) are in constant straight-line
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3 years ago
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