Explanation:
1) Based on the octet rule, iodine form an <u>I</u>⁻ ion.
Therefore,
Option E is correct ✔
2) The electronic configuration of the sulfide ion (S²⁻) is :
₁₆S = 1s² 2s² 2p⁶ 3s² 3p⁴ or [Ne] 3s² 3p⁴
₁₈S²⁻ = 1s² 2s² 2p⁶ 3s² 3p⁶ or [Ne] 3s² 3p⁶
Therefore,
Option E is correct ✔
3) valence shell electron of
Halogens = 7
Alkali metal = 1
Alkaline earth metal = 2
Therefore,
Option D is correct ✔
4) Group 2 element lose two electron in order to achieve Noble gas configuration.
And here Group 2 element is Sr
Therefore,
Option B is correct ✔
5) Group 13 element lose three electron in order to achieve Noble gas configuration.
And here Group 13 element is Al
Therefore,
Option B is correct ✔
6) For a given arrangements of ions, the lattice energy increases as ionic radius <u>decreases</u> and as ionic charge <u>increases</u>.
Therefore,
Option A is correct ✔
It is not important to accurately measure the amount of HCl placed in the eudiometer tube since HCl will be added in excess to react with all the moles of Mg.
In gas stoichiometry, through the method of displacement of a liquid (generally water), the gaseous byproduct is collected inside a long, thin graded glass tube called a eudiometer.
If we consider a reaction between Magnesium and Hydrochloric acid to give a product known as magnesium chloride and hydrogen gas, we can have the chemical equation represented as:
From the above reaction, for each mole of Magnesium taking place in the reaction, 1 mole of hydrogen gas is also produced.
Thus, we can have a prediction that HCl can always be added in excess in order for us to react to all the moles of solid magnesium, hence, it is not important to measure the moles of HCl since it will be added in excess.
Learn more about gas stoichiometry here:
brainly.com/question/32160?referrer=searchResults
Answer:
Option D. atm, L, K, mole
Explanation:
To know which option is correct, do the following:
We shall use the standard value for each variable to obtain the gas constant. This can be obtained as follow:
Volume (V) = 22400 mL
Pressure (P) = 760 mmHg
Number of mole (n) = 1 mole
Temperature (T) = 273 K
Gas constant (R) =?
PV = nRT
R = PV / nT
R = (760 × 22400) / (1 × 273)
R = 62358.97 mmHg.mL/Kmol
Volume (V) = 22.4 L
Pressure (P) = 760 mmHg
Number of mole (n) = 1 mole
Temperature (T) = 273 K
Gas constant (R) =?
PV = nRT
R = PV / nT
R = (760 × 22.4) / (1 × 273)
R = 62.359 mmHg.L/Kmol
Volume (V) = 22400 mL
Pressure (P) = 1 atm
Number of mole (n) = 1 mole
Temperature (T) = 273 K
Gas constant (R) =?
PV = nRT
R = PV / nT
R = (1 × 22400) / (1 × 273)
R = 82.05 atm.mL/Kmol
Volume (V) = 22.4 L
Pressure (P) = 1 atm
Number of mole (n) = 1 mole
Temperature (T) = 273 K
Gas constant (R) =?
PV = nRT
R = PV / nT
R = (1 × 22.4) / (1 × 273)
R = 0.0821 atm.L/Kmol
From the above illustrations, we can see that the gas constant will have a value for 0.0821 as long as other variables are: atm, L, K, mole
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.
Answer:
0.06 kg
Explanation:
Given data:
Mass of frisbee = ?
Velocity of frisbee = 11 m/s
Energy of frisbee = 3.6 j
Solution:
K.E = 1/2 mv²
Now we will put the values in this formula.
3.6 J = 1/2 m(11m/s)²
3.6 j = 0.5 ×121m²/s² × m
3.6 j = 60.5 m²/s² × m
m = 3.6 j/60.5 m²/s²
m= 0.06 j.m⁻².s²
j = Kg.m².s⁻²
m= 0.06 Kg.m².s⁻² .m⁻².s²
m = 0.06 kg
