Check the picture below.
so, a cone, that fits inside the cylinder, will have the same height "h" and radius "r". Thus
The angle is the arctangent of the ratio of ay to ax. Since ay is negative and ax is positive, it is a 4th-quadrant angle.
... arctan(ay/ax) = arctan(-4.00/3.90) ≈ 314.27°
... about 5.48513 radians
Answer:
Area = 32/3
Step-by-step explanation:
x = u
²
y = uv
z = 12v
²
0 ≤ u ≤ 2
0 ≤ v ≤ 1
Since ru = <2u, v, 0> and rv = <0, u, 24v>, we have
Where ru is the differentiation of x, y, z with respect to u and rv is the differentiation of x, y, z wit respect to v.
we find the cross product of ru and rv
ru × rv = 24v²i - 48uv²j + 2u²k
absolute value of ru × rv = 2u² + 24v²
We can now find the area
∫₀² du ∫₀¹ dv (2u² + 24v²) = ∫₀² du [2u²v + 8v³]₀¹ = 32/3
Detailed description can be found in the attachment
The area of <span>rhombus is product of two diagonals divided by 2
So you have 22 inches and 13 inches so that would be 22</span>·13/2 = 143
Final answer: 143 in²