Yes, they certainly do exist.
Do you have a question to ask ?
We have
We subtract 11x on both sides and 7 on both sides
we sum like terms
Then we isolate the x
ANSWER
x=-1
The equation only have one solution
Answer:
Step-by-step explanation:
Step-by-step explanation:
Familiarize yourself with perfect squares in the neighborhood of 140:
10^2 = 100
11^2 = 121
12^2 = 144
Note that 140 is much closer to the perfect square than it is to the perfect square 121. The value of √140 must lie closer to 12 than to 11.
Place a point on the number line about 3/4 of the way from 11 to 12.
Answer:69
Step-by-step explanation:
Note that (a+b)^2 = a^2 + 2ab + b^2. This is always true.
Let's re-write the given "<span>ab = 8 and a^2+b^2=16" as
a^2 + 2ab + b^2 = 16 + 2ab, or, equivalently, as
(a+b)^2 = 16 + 2(8) = 32.
This is the answer we wanted.
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