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kogti [31]
4 years ago
15

Brandy made a scale drawing of a house. The hall closet is 8 inches long in the drawing. The actual closet is 4 feet long. What

scale factor does the drawing use?
PLEASE HELP I NEVER SEEM TO GET THIS RIGHT PLEASE EXPLAIN HOW TO DO.
Mathematics
1 answer:
____ [38]4 years ago
3 0
Real is scaling down to the drawing, right? ...because she’d begin by measuring the real thing.
So that’s 4 ft to 8 inches, but that doesn’t make sense. They both have to be in the same measurement... either feet or inches. So 1 ft.= 12 in. So to change feet into inches, multiply 4x12= 48inches (In 4 feet) so 48 to 8 or48/8 which reduces to 8/1 a factor is Something multiplied together which means that as we started we have to scale it down that means that whatever we multiply by hast to make the answer smaller. That means that instead of scaling by 8 we’re going to scale by 1/8
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Need help with these problem, I really need help, thanks.
lisabon 2012 [21]
28. 20 cookies= 6 ounces
?=15 ounces
(20*15)/6 = 300/6 = 50 cookies
5 0
3 years ago
Give your answer as a whole number or as a mixed number in its simplest form.​
katrin2010 [14]

Answer:

5 3/7

Step-by-step explanation:

On this one all you basically have to do is 4+1 since they are both whole numbers, then attatch the fraction onto that.

4+1=5

5 3/7

6 0
2 years ago
A baseball player reaches first base 30% of the times he is at bat. Out of 50
Rasek [7]

Answer:

  • 15 times

Step-by-step explanation:

<u>The proportion is:</u>

  • k = 30% = 30/10 = 3/10

<u>Out of 50 times, the player will reach first base:</u>

  • 50*3/10 = 15 times
5 0
3 years ago
Read 2 more answers
evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha
dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

a

The Fermi function for the energy KT is  F(E_o) =  0.2689

b

The temperature is  T_k  =  1261 \  K

Step-by-step explanation:

From the question we are told that

   The energy considered is  E = 0.5 eV

Generally the Fermi  function is mathematically represented as

       F(E_o) =  \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }

    Here K is the Boltzmann constant with value k = 1.380649 *10^{-23} J/K

            E_F  is the Fermi energy

            E_o  is the initial energy level which is mathematically represented as

     E_o = E_F + KT

So

     F(E_o) =  \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{\frac{KT}{KT} } + 1}

=>   F(E_o) =  \frac{1}{e^{ 1 } + 1}

=>   F(E_o) =  0.2689

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the  Fermi  function as

     F(E_k) =  \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 }  = 0.01

HereE_k is that energy level that is  0.5 ev above the Fermi energy  E_k = 0.5 eV  + E_F

=>   F(E_k) =  \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 }  = 0.01

=>   \frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 }  = 0.01

=>   1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01

=>   0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }

=>   e^{\frac{0.50 eV ]}{KT_k} }  = 99

Taking natural  log of both sides

=>   \frac{0.50 eV }{KT_k} }  =4.5951

=>    0.50 eV   =4.5951 *  K *  T_k

Note eV is electron volt and the equivalence in Joule is     eV  =  1.60 *10^{-19} \  J

So

     0.50 * 1.60 *10^{-19 }   =4.5951 *  1.380649 *10^{-23} *  T_k

=>   T_k  =  1261 \  K

7 0
3 years ago
Pls help me to find the answer e,f,g,h no. only
Nikitich [7]

1. Change both numbers to common base.

2. Use quotient rule a^x \div a^y = a^{x-y}

e)

You can write 9 as 3², then both numbers have the same base.

9^x = (3^2)^x = 3^{2x}, where x is the exponent

I cannot really see the exponents because picture is bad quality.

9^x \div 3^y =

= (3^2)^x \div 3^y =

=3^{2x} \div 3^y =

= 3^{2x-y}

You want to replace x and y with actual numbers, but as I said the picture is too bad.

f)

Convert to base 4, then quotient rule.

g)

Use the quotient rule, you already have same base.

h)

Convert to base \frac{2}{3}, then quotient rule.

6 0
2 years ago
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