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givi [52]
3 years ago
13

Write an equation for a circle with a diameter that has endpointsat (-4, -7) and (-2 ,-5)

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:

(x + 3)^2 + (y + 6)^2 = (√2)^2 = 2

Step-by-step explanation:

The standard equation for a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.  We need to find h, k and r for this particular circle.

The length of the radius is half the length of the diameter.  Find the length of this diameter first, and than halve the result.

diameter^2 = 2^2 + 2^2, or diameter^2 = 8, or diameter = √8 = 2√2.

This is because x changes from -4 to -2 (+2) and y changes from -7 to -5 (+2).

Then the radius is r = 2√2.

The coordinates of the center are found using the midpoint formula:

                 -4-2

xcenter = -------- = -3

                    2

                 -7-5

ycenter = -------- = - 6

                     2

Inserting -3 for h, -6 for k and √2 for r, we get:

(x + 3)^2 + (y + 6)^2 = (√2)^2 = 2

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Step-by-step explanation:

Move the decimal place 4 tens places to the right (Positively)

51,760

I hope this helped!

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2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
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3√32x^4z

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(Square rooting the terms)

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7 0
3 years ago
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5. What is the graph of the equation?<br> -5x + y=-3
Mariulka [41]

Answer:

Plot y=5x-3

Step-by-step explanation:

6 0
3 years ago
A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?
Fynjy0 [20]

Answer:

The equation showing this situation is  D=b^2-4ac=0

Step-by-step explanation:

Given : A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

To find : Which could be the equation?  

Solution :

A quadratic equation in form ax^2+bx+c=0 has a solution x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} called a quadratic formula  in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If D=b^2-4ac>0 there are two real roots.

2) If D=b^2-4ac=0 there are one real roots.

3) If D=b^2-4ac there are no real roots.

According to question,

A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

So, The equation showing this situation is  D=b^2-4ac=0

6 0
3 years ago
What is the angle of C?
soldier1979 [14.2K]

Answer:

50°

Step-by-step explanation:

65 + 65 +C = 180

130+C = 180

C = 180 - 130 = 50

3 0
3 years ago
Read 2 more answers
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