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QveST [7]
3 years ago
10

I NEED HELP ASAP

Mathematics
2 answers:
Aliun [14]3 years ago
5 0

Answer:

y - 8 = \frac{5}{3}(x - 1)

Step-by-step explanation:

1) Use the slope formula, \frac{y_2 - y_1}{x_2 - x_1}, and the given points to find the slope. x_1 and y_1 represent the x and y values of one point the line must intersect, and x_2 and y_2 represent the x and y values of another point the line must also intersect:

\frac{(3)-(8)}{(-2)-(1)}

= \frac{-5}{-3}

= \frac{5}{3}

2) Using the point-slope formula, y-y_1 = m (x - x_1), use the slope you just calculated and substitute it for m. Choose any of the two points given (I chose (1,8)) and substitute its x and y values for x_1 and y_1. Don't worry, the equation of the line is the same no matter which point you choose (unless the question specifies which one you need to choose):

y - 8 = \frac{5}{3}(x - 1)

Lubov Fominskaja [6]3 years ago
3 0
We first solve to find the slope. The slope of the line is 5/3. Then we substitute that into the formula that is y-y1=m(x-x1). M represents the slope of the line and the x and y’s represent the point values. So we get 8-3=5/3(1+2). We get this solution if it asks you to figure out the slope along the way too.

If they ask you the equation when knowing only the two points you do 8-3=m(1+3)

They both mean the same thing ( it just depends on what the problem is specifically asking you about)
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Read 2 more answers
Write an equation for the line perpendicular to the line y= -2/3+7 which passes through the point (-5,6)
zysi [14]
Y = -2/3x + 7.....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. All tht means is take the original slope, flip it, and change the sign. So we take -2/3....flip it making it -3/2.....change the sign making it 3/2. So ur perpendicular line will have a slope of 3/2.

y = mx + b
slope(m) = 3/2
(-5,6)....x = -5 and y = 6
now sub and find b, the y int
6 = 3/2(-5) + b
6 = -15/2 + b
6 + 15/2 = b
12/2 + 15/2 = b
27/2 = b
so ur perpendicular equation is : y = 3/2x + 27/2 <==
8 0
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