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4 years ago

Can anybody tell me the answer for this 11/12-1/3

Mathematics

2 answers:

solniwko [45]4 years ago

6 0

Answer:

7/12 + 2q/3

Step-by-step explanation:

11/12 - 1/3

= 11/12 - 4/12

=(11-4)/12

= 7/12

All the picture:

11/12 - 1q/6 + 5q/6 - 1/3

= 11/12 - 1/3 - 1q/6 + 5q/6

= 7/12 + 4q/6

= 7/12 + 2q/3

juin [17]4 years ago

4 0

Answer:

7-8q/12 is the answer

i aspect that it will be helpful for you

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What is the mean of 10,12,15,11

Mrrafil [7]

Answer:

Step-by-step explanation:

To find the mean of a set of numbers, add all the numbers together. Then, divide the sum by how many numbers you had to begin with.

Add the numbers together:

10 + 12 + 15 + 11

= 48 This is the sum of the data

Count how many numbers you had:

10, 12, 15 and 11 are FOUR numbers (amount of data).

Divide the sum of the data by the amount of data.

48 ÷ 4 = 12 This is the mean

The mean of 10, 12, 15, 11 is 12.

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3 years ago

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3) x2+ y2 - x + 3y - 42 = 0<br> X+y=4

REY [17]

The solution is $(-1,5)$ and $(7,-3)$

Step-by-step explanation:

The expression is $x^{2} +y^{2} -x+3y-42=0$ and $x+y=4$

Using substitution method we can solve the expression.

Let us substitute $x=4-y$ in $x^{2} +y^{2} -x+3y-42=0$

$(4-y)^{2} +y^{2} -(4-y)+3y-42=0$

Expanding and simplifying the expression, we get,

$\begin{array}{r}{16-8 y+y^{2}+y^{2}-4+y+3 y-42=0} \\{2 y^{2}-4 y-30=0}\end{array}$

Let us use the quadratic equation formula to solve this equation,

$\begin{aligned}y &=\frac{4 \pm \sqrt{16-4(2)(-30)}}{2(2)} \\&=\frac{4 \pm \sqrt{16+240}}{4} \\&=\frac{4 \pm 16}{4} \\y &=1 \pm 4\end{aligned}$

Thus, $y=5$ and $y=-3$

Substituting y-values in the equation $x+y=4$ , we get the value of x.

For $y=5$ ⇒ $x=4-5=-1$

For $y=-3$ ⇒ $x=4+3=7$

Thus, the solution set is $(-1,5)$ and $(7,-3)$

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4 years ago

Triangle ABC is isosceles where AC = CB. AC = 6a - 8 and CB = 4a - 2. Find AC.

anastassius [24]

Answer:

Step-by-step explanation:

AC = CB

6a - 8 = 4a - 2

a = 3

6(3) - 8 = 10

AC = 10

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