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11111nata11111 [884]
3 years ago
8

Which of these are linear functions?

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

B, D, E

Step-by-step explanation:

Use a graphing calculator.

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Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

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So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

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P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

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