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Tju [1.3M]
3 years ago
7

Use the diagram to find the measure of arc. AB and CD and the diameters of the circle F

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Answer:

11). m(\widehat{DE}) = 90°

12). m(\widehat{AEC}) = 212°  

Step-by-step explanation:

A circle F with AB and CD are the diameters has been given in the figure attached.

11). Since, m(\widehat{AB}) = 180°

    and m(\widehat{AB})=m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE})

    Therefore, m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE}) = 180°

    32° + m(\widehat{DE}) + 58° = 180°

    m(\widehat{DE}) = 180° - 90°

                = 90°

12. Since, m(\widehat{AD})=m(\widehat{BC}) = 32°

                 m(\widehat{AEC}) = m(\widehat{AB})+m(\widehat{BC})

                                = 180° + 32°

                                = 212°

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VW = VC + CW
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3 years ago
Mai received and spent money in the following ways last month. For each example, write a signed number to represent the change i
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6 0
3 years ago
40% of what number is 14
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8 0
4 years ago
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Learning Task 3:
padilas [110]

Answer:

Area = x^2- 25

Area =9x^2 +24x + 16

Length = (3x -2)

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Product = 3m^3 + 6m^2 - 6m

Step-by-step explanation:

Solving (1):

Length = (x + 5)

Width = (x - 5)

Required

Calculate Area

Area = Length * Width

Area = (x + 5) * (x - 5)

Area = x^2 + 5x - 5x - 25

Area = x^2- 25

Solving (2):

Given

Length = (3x + 4)

Required: Calculate Area

Area =Length * Length

Area =(3x + 4) * (3x + 4)

Area =9x^2 + 12x + 12x + 16

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Solving (3):

Area = 3x^2 + 7x - 6

Width = x + 3

Required: Calculate Length

Area = Length * Width

Length = \frac{Area}{Width}

Length = \frac{3x^2 + 7x - 6}{x + 3}

Factorize the numerator

Length = \frac{3x^2 + 9x -2x - 6}{x + 3}

Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}

Length = \frac{(3x -2) (x + 3)}{x + 3}

Divide by x + 3

Length = (3x -2)

Solving (4):

Distance = (2y^3 - 7y^2 + 5y -1)

Time = 2y - 1

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This is calculated as:

Speed = \frac{Distance}{Time}

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Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}

Speed = \left(y^2-3y+1\right)

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Multiply (m^2 + 2m - 2) by sum of (m + 3) and (2m - 3)

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Sum = m + 3 + 2m - 3

Sum = m +  2m+3 - 3

Sum = 3m

Then, the product

Product = (m^2 + 2m - 2)(3m)

Product = 3m^3 + 6m^2 - 6m

6 0
3 years ago
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alukav5142 [94]

Step-by-step explanation:

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