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2 years ago

Anyone know the answer to x^2 - 11x + 18 = 0

Mathematics

2 answers:

Artyom0805 [142]2 years ago

6 0

Two solutions are found
1. x=9
2. x=2

Digiron [165]2 years ago

5 0

Answer:

x= 9, x= 2

Step-by-step explanation:

x^2- 2x- 9x+ 18= 0

x (x-2) -9 (x-2)

(x-9) (x-2)

x-9= 0, x-2= 0

Therefore, x= 9, x= 2

If you don't mind, plz mark me brainliest

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Krutika was thinking of a number. Krutika adds 4 to it, then doubles it and gets an answer of 83.9. What was the original number

mr Goodwill [35]

Answer:37.95

Step-by-step explanation:

8 0

2 years ago

"Raju's father age is 5 years more than three times of Raju's age. Raju's father age is 50 years."

Lana71 [14]

Let rajus age be x

His father=3x+5

ATQ

$\\ \bull\tt\longmapsto 3x+5=50$

$\\ \bull\tt\longmapsto 3x=50-5$

$\\ \bull\tt\longmapsto 3x=45$

$\\ \bull\tt\longmapsto x=\dfrac{45}{3}$

$\\ \bull\tt\longmapsto x=15$

8 0

2 years ago

Read 2 more answers

In a group of 58 learners at Nakambuda C.S, 34 learners have chosen the field of Agriculture. What fraction of learners will be

asambeis [7]

learners of Agriculture: 34/58

semplify it

divide by 2

34 > 17

58 > 29

they are prime numbers, so can't be semplify anymore

17/29 will do Agriculture

in percentage we have a proportion:

17 : 29 = x : 100

x = (17 * 100) / 29 = 1700 / 29 ≅ 48,62

4 0

2 years ago

One of the relatively uncommon instances in which researchers know the population standard deviation is in the case of the Intel

Phoenix [80]

Answer:

90% confidence interval for the mean IQ score in this community is [106.58 , 109.42].

Step-by-step explanation:

We are given that in general, the average IQ score in large, diverse populations is 100 and the standard deviation is 15.

Suppose that your sample of 300 members of your community gives you a mean IQ score of 108.

Firstly, the pivotal quantity for 90% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean IQ score = 108

$\sigma$ = population standard deviation = 15

n = sample of members = 300

$\mu$ = population mean IQ score

Here for constructing 90% confidence interval we have used One-sample z test statistics because we know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $108-1.645 \times {\frac{15}{\sqrt{300} } }$ , $108+1.645 \times {\frac{15}{\sqrt{300} } }$ ]

= [106.58 , 109.42]

Therefore, we can be 90% confident that the mean IQ score in this community lies between 106.58 and 109.42.

8 0

3 years ago

The population was decreased by 300 residents over the past 5 years.The same number of residents left each year what was the cha

Sonja [21]

Answer:

the answer is 60 per year

Step-by-step explanation:

300/5=60

3 0

3 years ago