Answer: the golf ball with hit the ground again after 2.75 seconds
Step-by-step explanation:
The movement of the golf ball from the ground follows the equation h(t)=-16t^2+44t,
where t is the time in seconds, and h(t) is the height of the ball at a given time t
By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes
-16t^2+44t = 0
Dividing both sides by t
16t^2/t = 44t/t
16t = 44
t = 44/16
t = 2.75
If this is a actual question then you are missing parts of it! Please leave a comment with the full question and I would be glad to help you out! If looking at what is given then 0 apples as all that is stated is only 48 oranges and no apples.
Answer:
Step-by-step explanation:
Since angles A and E correspond, as well as angles C and F, we can say ...
ΔABC ~ ΔEDF
Then the ratio of side lengths of ΔABC to those of ΔEDF is ...
AC/EF = 6/2 = 3
That means ...
ED/AB = 1/3
ED = AB·(1/3) = 3.3·(1/3) = 1.1
For the remaining sides, we have the relation
3·DF = BC
3·(BC -3.2) = BC
2BC - 9.6 = 0 . . . eliminate parentheses, subtract length BC
BC -4.8 = 0 . . . . . divide by 2
BC = 4.8 . . . . . . . . add 4.8
DF = BC·(1/3) = 1.6
The unknown side lengths are BC = 4.8, DE = 1.1, DF = 1.6.
