The product of 13 and m plus the product of 2.7 and n

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

6 0

13m+2.7n

If thats what you need

Art [367]2 years ago

4 0

Answer:

13 m + 2.7 n.

Step-by-step explanation:

Given : the product of 13 and m plus the product of 2.7 and n

To find : Write expression .

Solution : We have given

Product of 13 and m = 13 * m

Product of 2.7 and n = 2.7 * n

According to question :

Sum of Product of 13 and m and Product of 2.7 and n

13 *m + 2.7 *n

13 m + 2.7 n.

Therefore, 13 m + 2.7 n.

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Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.

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$\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }$

Solution:

From given question,

Number of pounds Jake carry = $6\frac{1}{4} \text{ pounds }$

Number of pounds his father carry is $1\frac{5}{7}$ times as much as jake

To find: Number of pounds Jake father can carry

Convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

$\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}$

Then according to question,

$\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}$