At at least one die come up a 3?We can do this two ways:) The straightforward way is as follows. To get at least one 3, would be consistent with the following three mutually exclusive outcomes:the 1st die is a 3 and the 2nd is not: prob = (1/6)x(5/6)=5/36the 1st die is not a 3 and the 2nd is: prob = (5/6)x((1/6)=5/36both the 1st and 2nd come up 3: prob = (1/6)x(1/6)=1/36sum of the above three cases is prob for at least one 3, p = 11/36ii) A faster way is as follows: prob at least one 3 = 1 - (prob no 3's)The probability to get no 3's is (5/6)x(5/6) = 25/36.So the probability to get at least one 3 is, p = 1 - (25/36) = 11/362) What is the probability that a card drawn at random from an ordinary 52 deck of playing cards is a queen or a heart?There are 4 queens and 13 hearts, so the probability to draw a queen is4/52 and the probability to draw a heart is 13/52. But the probability to draw a queen or a heart is NOT the sum 4/52 + 13/52. This is because drawing a queen and drawing a heart are not mutually exclusive outcomes - the queen of hearts can meet both criteria! The number of cards which meet the criteria of being either a queen or a heart is only 16 - the 4 queens and the 12 remaining hearts which are not a queen. So the probability to draw a queen or a heart is 16/52 = 4/13.3) Five coins are tossed. What is the probability that the number of heads exceeds the number of tails?We can divide
2km=2 kilometer
kilo=1000 so 2 km=2000m
25m
2500cm
cm=centimeter=1/100 of a meter
so
2500cm=25m
mm=milimeter=1/1000 meter
so
3000mm=3m
so the longets is obviously 2000m or 2km
Answer:
924
Step-by-step explanation:
i multiply 14 by 11 and then by 6
Answer:
g(x) = x^2 -6x +9
Step-by-step explanation:
A function f(x) translated right h units and up k units will become ...
g(x) = f(x -h) +k
You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...
g(x) = f(x -3) = (x -3)^2
g(x) = x^2 -6x +9
Answer:
0033
Step-by-step explanation:
.033 of a whole number so its .033
