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Lyrx [107]
3 years ago
13

Suppose that the mean GRE score for the USA is 500 and the standard deviation is 75. Use the Empirical Rule (also called the 68-

95-99.7 Rule) to determine the percentage of students likely to get a score between 350 and 650? What percentage of students will get a score above 500?
Mathematics
1 answer:
evablogger [386]3 years ago
5 0
The Empirical Rule is saying that 68% of students are only 1 std deviation from the mean, 95% are 2 std deviations from the mean.

Find how many std deviations 350 and 650 are from the mean of 500.
350 - 500 = -150    ----> -150/75 = -2
650 - 500 = 150    ----> 150/75 = 2

Each are 2 std deviations from the mean. This means that about 95% of students are between 350 and 650.

By definition, 50% will be above the mean and below the mean.
Therefore 50% of the students will get a score above 500.

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The ratio of legs to dogs in the cat shelter was 4 to 1. If there were 8 cats , then how many cats were there?
andrezito [222]

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Step-by-step explanation:

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Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

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3 years ago
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