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Lyrx [107]
3 years ago
13

Suppose that the mean GRE score for the USA is 500 and the standard deviation is 75. Use the Empirical Rule (also called the 68-

95-99.7 Rule) to determine the percentage of students likely to get a score between 350 and 650? What percentage of students will get a score above 500?
Mathematics
1 answer:
evablogger [386]3 years ago
5 0
The Empirical Rule is saying that 68% of students are only 1 std deviation from the mean, 95% are 2 std deviations from the mean.

Find how many std deviations 350 and 650 are from the mean of 500.
350 - 500 = -150    ----> -150/75 = -2
650 - 500 = 150    ----> 150/75 = 2

Each are 2 std deviations from the mean. This means that about 95% of students are between 350 and 650.

By definition, 50% will be above the mean and below the mean.
Therefore 50% of the students will get a score above 500.

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Step-by-step explanation:

We are given the following in the question:

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A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

y - y_1 = m(x - x_1)

The point intercept form of line can be written as:

y = mx + c

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10

which is the required slope intercept equation of line p.

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\large\boxed{x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}}

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\sin x-(3\sin x-1)=0\\\\\sin x-3\sin x+1=0\qquad\text{subtract 1 from both sides}\\\\-2\sin x=-1\qquad\text{divide both sides by 2}\\\\\sin x=\dfrac{1}{2}\Rightarrow x=\dfrac{\pi}{6}+2k\pi\ \vee\ x=\dfrac{5\pi}{6}+2k\pi,\ k\in\mathbb{Z}

\text{Equation:}\\\\\sin x=a\\\\\text{has solutions}\\\\x=\theta+2k\pi\ \vee\ x=(\pi-\theta)+2k\pi\\\\\text{Why}\ 2k\pi?\\\text{Because the sine function has a period of}\ 2\pi.

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