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Sergeeva-Olga [200]
3 years ago
10

Select an expression equal to 6(4q + 8r)​

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0

Answer: B: 24q+48r

Step-by-step explanation: 6(4q+8r)

=(6)(4q+8r)

=(6)(4q)+(6)(8r)

=24q+48r

 

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A phone company charges a $35 fee for signing up for their service plan and $40 for each month of service. Write a linear equati
anyanavicka [17]

Answer:

y = 40x + 35

Step-by-step explanation:

Let x represent each month of service in the equation

Since it is $40 for each month, the price for each month can be represented by 40x.

The $35 fee will represent the y intercept, and will be added to 40x in the equation.

Put this together in the equation y = mx + b

y = 40x + 35

So, the linear equation to model the situation is y = 40x + 35

7 0
3 years ago
-(18+4x)=8 hope you can help
Step2247 [10]
-1(18+4x)=8
Then you distribute
-18-4x=8
-4x=26
X= -6.5
4 0
4 years ago
Read 2 more answers
Juan paga por un saco S/ 224, después de que le han
grigory [225]

El saco tiene un precio original de 400 soles.

<h3>¿Cómo determinar el precio inicial de un saco comprado con descuento?</h3>

En este problema tenemos el caso de un precio de compra (P'), en soles, que es resultado de aplicar dos descuentos consecutivos al precio original del saco (P), en soles. El precio es el resultado de multiplicar el precio original por los dos factores de porcentaje, descrito por la siguiente fórmula:

P' = P · (1 - r₁ / 100) · (1 - r₂ / 100), 0 ≤ r₁, r₂ ≤ 100.

Donde:

  • r₁ - Porcentaje del primer descuento.
  • r₂ - Porcentaje del segundo descuento.

Si sabemos que P' = 224, r₁ = 30 y r₂ = 20, entonces el precio original del saco es:

224 = (1 - 30 / 100) · (1 - 20 / 100) · P

224 = 0.7 · 0.8 · P

P = 224 /(0.7 · 0.8)

P = 400

El precio original del saco es de 400 soles.

Para aprender más sobre descuentos: brainly.com/question/24130820

#SPJ1

5 0
1 year ago
I need answer immediately!!!!!
yan [13]

6 blocks :) I won’t explain it tho lol

4 0
3 years ago
James believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request.
Dimas [21]
315/356 = about 0.88 or 88%. <span>
64/144= about .044 or 44%

</span><span>They will not have equal opportunity to get the math class they requested, if both percents were equal, it would be fair. For honors students, 88% of them will get the class they requested, but for non honors students it's 44%.</span>
3 0
3 years ago
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