Answer:
- 1,7
Step-by-step explanation:
but not sure on this if wrong so sorry
Answer:
4.589×10to the power of -11
Step-by-step explanation:
To find the total area of this figure, it would be easiest to find the area of the left part (rectangle) and then find the area of the right part (triangle), and then add the two area values together.
First, we will find the area of the rectangle, using the formula A = lw, where l is the length of the rectangle and w is the width of the rectangle.
The length of the rectangle is 13 cm and the width is 9 cm. If we substitute in these values into our equation, we get:
A = (13cm)(9cm)
A= 117 cm^2
Next, let’s find the area of the triangle, using the formula A=(1/2)bh, where b is the base of the triangle and h is the height.
The base of the triangle is 11 cm and the height of the triangle is 5 cm (found by subtracting 13-8 as seen in the figure). If we substitute in these values and simplify, we get:
A=1/2(11cm)(5cm)
A=1/2(55cm^2)
A=27.5 cm^2.
When we add together the area of the rectangle with the area of the triangle, we will get the total area of the figure.
117 cm^2 + 27.5 cm^2 = 144.5 cm^2
Your answer is 144.5 cm^2 or the first option.
Hope this helps!
What you are doing with proportions most the time is solving for a variable which in this example I will use an x. You have to do something called cross multiplying. now look at number 21. when you cross multiply you multiply the number of the top part of the fraction on the left side to the bottom part of the fraction on the right side. In that example 1 × 36 = 36. now write 36 = 16x since you have to cross multiply the other parts of the fraction. Then you would divide both sides of the equation by 16. I will make a mixed fraction for this example. 2 4/16 which simplified equals 2 1/4
Answer:
It takes 6 men 3 days to lay the foundations of a building of size 30m^2
.
On one site they have to lay the foundations of a building of size 50m2 and it needs to be completed in 2 days.
How many men will they need?
Step-by-step explanation:
