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gogolik [260]
2 years ago
10

Joseph has 22 gallons of fertilizer. He uses 7 quarts to fertilize his plants.

Mathematics
1 answer:
nata0808 [166]2 years ago
5 0
Joseph would have 81 quarts of fertilizer left
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s2008m [1.1K]

Answer:

Step-by-step explanation:

6X6 is 36 so it is increasing

8 0
2 years ago
Read 2 more answers
Rachel multiplied each side of x ≥ 2 by 3. She wrote the result as 3x ≤ 6. Explain the error Rachel made.
andrey2020 [161]

Answer:

Her mistake was to change the inequality sign from ≥ to ≤.

The sign only changes when you multiply or divide both sides of an inequality by a negative number.

6 0
2 years ago
A rectangular storage container with an open top is to have a volume of 24 cubic meters. The length of its base is twice the wid
Mariana [72]

Answer:

419.25

Step-by-step explanation:

The calculation of the cost of materials for the cheapest such container is shown below:-

We assume

Width = x

Length = 2x

Height = h

where, length = 2 \times width

Base area = lb

= 2x^2

Side area = 2lh + 2bh

= 2(2x)h + 2(x)h

= 4xh + 2xh

Volume = 24 which is lbh = 24

h = \frac{24}{2x^2} \\\\ h = \frac{12}{x^2}

Now, cost is

= 13(2x^2) + 9(4xh + 2xh)\\\\ = 13(2x^2) + 9(4x + 2x)\times \frac{12}{x^2} \\\\ = 26x^2 + \frac{648}{x}

now we have to minimize C(x)

So, we need to compute the C'(x)

= 52x - \frac{648}{x^2}

C"(x)  = 52x - \frac{1,296}{x^3}

now for the critical points, we will solve the equation C'(x) = 0

= 52x - \frac{648}{x^2} = 0\\\\ x = \frac{648}{52}^{\frac{1}{3}}

C" = ((\frac{648}{52} ^{\frac{1}{3} } = 52 + \frac{1296}{(\frac{648}{52})^\frac{1}{3} )^3}\\\\ = 52 + \frac{1296}{\frac{648}{52} } >0

So, x is a point of minima that is

= (\frac{648}{52} )^\frac{1}{3}

Now, Base material cost is

= 13(2x^2)\\\\ = 26(\frac{648}{52} )^\frac{2}{3}

= 139.75

Side material cost is

= \frac{648}{x} \\\\ = \frac{648}{(\frac{648}{52})^\frac{1}{3}  }

= 279.50

and finally

Total cost is

= 139.75 + 279.50

= 419.25

4 0
3 years ago
What is the total surface area
Stels [109]

We have two right triangles and three different rectangles.

The formula of an area of a right triangle:

A_T=\dfrac{1}{2}l_1l_2

l₁, l₂ - legs

We have l₁ = 20cm and l₂ = 21cm. Substitute:

A_T=\dfrac{1}{2}(20)(21)=(10)(21)=210\ cm^2

The formula of an area of a rectangle:

A_R=lw

l - length

w - width

We have:

rectangle #1: l = 22cm, w = 29cm

A_{R1}=(22)(29)=638\ cm^2

rectangle #2: l = 22cm, w = 21cm

A_{R2}=(22)(21)=462\ cm^2

rectangle #3: l = 22cm, w = 20cm

A_{R3}=(22)(20)=440\ cm^2

The total Surface Area of the triangular prism:

S.A.=2A_T+A_{R1}+A_{R2}+A_{R3}\\\\S.A.=2\cdot210+638+462+440=1960\ cm^2

3 0
2 years ago
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