1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mr_godi [17]
3 years ago
12

What is 50 times 100

Mathematics
2 answers:
MArishka [77]3 years ago
4 0
5,000
You would do 5 x 1= 5 and then add the three zeros
Airida [17]3 years ago
4 0
The answer is 5000 so i hope this helps 



You might be interested in
What values of b satisfy 3(2b + 3)2 = 36?
Vlad1618 [11]

Exact Form:

b =  3/2

Decimal Form:

b =  1.5

Mixed Number Form:

b  =  1  1/2

Hope This Helps You!

Please mark as brainlest if possible!

6 0
2 years ago
Heather opens a bank account with $125. Each week, starting the following week, she deposits $25 into her account.
vichka [17]
The equation is y=25n+125 I think
3 0
3 years ago
Read 2 more answers
Write the fractional equivalent (in reduced form) of each number.
garik1379 [7]
0.1 = 1/10 

0.16 = 16/100 = 8/50 = 4/25 

0.6 = 6/10 = 3/5 

0/6 = 6/10 = 3/5 
5 0
3 years ago
Read 2 more answers
Population Growth A lake is stocked with 500 fish, and their population increases according to the logistic curve where t is mea
Alexus [3.1K]

Answer:

a) Figure attached

b) For this case we just need to see what is the value of the function when x tnd to infinity. As we can see in our original function if x goes to infinity out function tend to 1000 and thats our limiting size.

c) p'(t) =\frac{19000 e^{-\frac{t}{5}}}{5 (1+19e^{-\frac{t}{5}})^2}

And if we find the derivate when t=1 we got this:

p'(t=1) =\frac{38000 e^{-\frac{1}{5}}}{(1+19e^{-\frac{1}{5}})^2}=113.506 \approx 114

And if we replace t=10 we got:

p'(t=10) =\frac{38000 e^{-\frac{10}{5}}}{(1+19e^{-\frac{10}{5}})^2}=403.204 \approx 404

d) 0 = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And then:

0 = 7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)

0 =19e^{-\frac{t}{5}} -1

ln(\frac{1}{19}) = -\frac{t}{5}

t = -5 ln (\frac{1}{19}) =14.722

Step-by-step explanation:

Assuming this complete problem: "A lake is stocked with 500 fish, and the population increases according to the logistic curve p(t) = 10000 / 1 + 19e^-t/5 where t is measured in months. (a) Use a graphing utility to graph the function. (b) What is the limiting size of the fish population? (c) At what rates is the fish population changing at the end of 1 month and at the end of 10 months? (d) After how many months is the population increasing most rapidly?"

Solution to the problem

We have the following function

P(t)=\frac{10000}{1 +19e^{-\frac{t}{5}}}

(a) Use a graphing utility to graph the function.

If we use desmos we got the figure attached.

(b) What is the limiting size of the fish population?

For this case we just need to see what is the value of the function when x tnd to infinity. As we can see in our original function if x goes to infinity out function tend to 1000 and thats our limiting size.

(c) At what rates is the fish population changing at the end of 1 month and at the end of 10 months?

For this case we need to calculate the derivate of the function. And we need to use the derivate of a quotient and we got this:

p'(t) = \frac{0 - 10000 *(-\frac{19}{5}) e^{-\frac{t}{5}}}{(1+e^{-\frac{t}{5}})^2}

And if we simplify we got this:

p'(t) =\frac{19000 e^{-\frac{t}{5}}}{5 (1+19e^{-\frac{t}{5}})^2}

And if we simplify we got:

p'(t) =\frac{38000 e^{-\frac{t}{5}}}{(1+19e^{-\frac{t}{5}})^2}

And if we find the derivate when t=1 we got this:

p'(t=1) =\frac{38000 e^{-\frac{1}{5}}}{(1+19e^{-\frac{1}{5}})^2}=113.506 \approx 114

And if we replace t=10 we got:

p'(t=10) =\frac{38000 e^{-\frac{10}{5}}}{(1+19e^{-\frac{10}{5}})^2}=403.204 \approx 404

(d) After how many months is the population increasing most rapidly?

For this case we need to find the second derivate, set equal to 0 and then solve for t. The second derivate is given by:

p''(t) = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And if we set equal to 0 we got:

0 = \frac{7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)}{(1+19e^{-\frac{t}{5}})^3}

And then:

0 = 7600 e^{-\frac{t}{5}} (19e^{-\frac{t}{5}} -1)

0 =19e^{-\frac{t}{5}} -1

ln(\frac{1}{19}) = -\frac{t}{5}

t = -5 ln (\frac{1}{19}) =14.722

7 0
2 years ago
There are 12 squares and 4 triangles. What is the equation that compares the number of squares s to the number of triangles t?
anastassius [24]
12subtract4
12-4
they want me to write more then 20 charaters

4 0
3 years ago
Other questions:
  • A seafood restaurant claims an increase of 1,750.00 over its average profit during a week where it introduced a special of baked
    13·1 answer
  • A pizzeria makes pizzas in the shape of a regular octagon, and cuts them into 8 identical triangular slices. The diameter of the
    7·1 answer
  • Plz help! Convert 3/5 into fractions with a denominater of 15 A.9/15 B. 3/15 C.5/15 D. 6/15
    13·1 answer
  • 12 × 6 = 72
    8·2 answers
  • Determine the number of real solutions the equation has.
    7·1 answer
  • The circumference of a circle is 32 centimeters. Which is closest to the radius? A. 10.2 centimeters B. 5.1 centimeters C. 16 ce
    11·2 answers
  • Explain why triangle pqs is isosceles
    10·1 answer
  • 11.What is 1.24 written as a percent?
    7·1 answer
  • Solve using the elimination method <br>x + 5y = 26 <br>- X+ 7y = 22​
    7·2 answers
  • What is the area of a circle with a radius of 21?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!