What is 50 times 100

Please help asap!!! i’ll rate you most brainliest

SSSSS [86.1K]

I’m pretty sure it’s D??? But it also could be B I’m sorry :( trying to help as much as possible

6 0

3 years ago

Explain the difference between deductive and inductive arguments in your own words.

lyudmila [28]

Answer: The difference is as follows:

Step-by-step explanation:

Deductive Arguments: A deductive argument is an argument wherein it is felt that the premises give an assurance of reality of the end. In a deductive arguments, the premises are planned to offer help for the conclusion that is so strong to an extent that, if the premises are valid, it would be impossible for the conclusion to be false.

Inductive Arguments: An inductive arguments is an arguments where it is believed that the premises provide reasons supporting the likely truth of the conclusion. In an inductive arguments, the premises are proposed distinctly to be strong to an extent that, on the off chance that they are valid, at that point it is impossible that the conclusion is false.

The contrast between the two originates from the kind of connection the author or explainer of the argument takes there to be between the premises and the conclusion. In the event that the author of the argument accepts that reality of the premises certainly sets up reality of the conclusion because of definition, l<igical entailment or scientific need, at that point the argument is deductive. In the event that the author of the argument does not feel that reality of the premises certainly sets up reality of the conclusion, however in any case accepts that their fact gives valid justification to accept the conclusion genuine, at that point the argument is inductive.

5 0

3 years ago

The board of an internet start up company has sixteen members. if one person is in charge of research and one is in charge of ma

Brilliant_brown [7]

The number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

The permutation is the way of choosing a set of objects from a larger set of objects in a specific sequence.

If we are choosing r number of objects, from n number of objects in a specific sequence, then we follow permutation, and it is given as:

nPr = n!{(n - r)!}.

In the question, we are asked to find the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members.

Since the position is to be chosen in a specific order, we will follow permutation.

The number of positions to be chosen (r) = 2.

The number of members (n) = 16.

Thus, the number of ways is given as:

nPr = n!{(n - r)!},

or, 16P2 = 16!{(16 - 2)!},

or, 16P2 = 16!/14! = 15*16 = 240.

Thus, the number of ways in which the position of one person in charge of research and one person in charge of marketing can be chosen from the board of 16 members is <u>240 ways</u>. Computed using permutations.

Learn more about permutations at

brainly.com/question/4658834

#SPJ4

6 0

2 years ago

The number part when a number and a variable are multiplied together in a term is called the _____.

77julia77 [94]

Answer:

Coefficient

Step-by-step explanation:

-Usually a combination of variables and constants are multiplied to get a product.

-The constant or number part in the multiplication process is called the Coefficient

7 0

3 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago