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julia-pushkina [17]
3 years ago
5

If AC=20, AE =25, and AB=5, what is the length of AD

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

I need te picture of the shape to solve this

Step-by-step explanation:

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Answer:

1: Out: 5, 8, 11, 14

2: Out: 2, 7, 10, 11

3: Out: 11  Rule: Add 4

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2 years ago
What is the distance from point A to point D on the number line?
mrs_skeptik [129]
The answer would be 3.5
7 0
4 years ago
Kevin counts 75 chicks in the hen house. He also sees more chicks outside the hen house. How can Kevin count to find how many ch
stellarik [79]

What we know:

we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks

What we need to find:

we need to find out how many chicks were outside

Answer equation:

108 - 75 = 33

8 0
3 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
Give an example from your classroom of three collinear points
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Chess board? , the board if there is like a line with points that has points on the same line. 
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3 years ago
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