What is the domain of the function y=2√x-5 A. x≥-5 B. x≥2 C. x≥5 D. x≥10

I have been stuck on this question for a while(NO SPAMMING IT IS ANNOYING)The formula used to find the area of a circle is πr² (

RoseWind [281]

Answer:

200.96

or

201 (if you round it up)

Step-by-step explanation:

1) Well, if we know that the diameter (D) is 16 cm, then we know that the radius (r) is 8 cm (D = 2 * r).

2) Next, we square (^2) the radius, and we get 64 (r^2 = r * r = 8*8 = 64)

3) Finally, we multiply π by 64, and we get 200.96 cm^2 (3.14 * 64) which is very close to 201 cm^2.

3 0

3 years ago

If y-18=14, what is the value of 2(y+9)?

stealth61 [152]

------------------------------------------------------------------------
Find the value of y
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y - 18 = 14
+ 18 + 18

y = 32
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substitute y = 32 into 2 (y + 9)
------------------------------------------------------------------------

2( y + 9 ) = 2 ( 32 + 9 )
2 (y + 9 ) = 2 (41)
2 ( y + 9 ) = 82

------------------------------------
Answer: 82
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5 0

3 years ago

Read 2 more answers

ASAP PLSSS!! Find the slope of the line shown below :

Marta_Voda [28]

Answer:

the slope is 3

Step-by-step explanation:

5 0

2 years ago

1.44 Make-up exam: In a class of 28 students, 27 of them took an exam in class and 1 student took a make-up exam the following d

Olenka [21]

Answer:

a) Decrease

b) New mean = 78.43

c) Decrease

Step-by-step explanation:

We are given the following in the question:

Total number of students in class = 28

Average of 27 students = 79

Standard Deviation of 27 students = 6.5

New student's score = 63

a) The new student's score will decrease the average.

b) New mean

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean = \dfrac{\displaystyle\sum x_i}{27} = 79\\\\\sum x_i = 27\times 79 = 2133$

New mean =

$\text{ New mean} =\dfrac{ \displaystyle\sum x_i +63}{28}\\\\ =\dfrac{2133+63}{28}= \dfrac{2196}{28} = 78.43$

Thus, the new mean is 78.43

c) Since the new mean decreases, standard deviation for new scores will decrease.

This is because the new value is within the usual values i.e. within two standard deviations of the mean. So, this wont cause a lot of variation as this value will be closer to already available data values. Also number of observations (n) in the denominator is increasing. Based on both these points we can conclude that standard deviation will decrease

Formula for Standard Deviation:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n}}$