The ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28
<h3>How to find the Mean Absolute Deviation?</h3>
From the given table, we see that;
Mean grade of Sidney = 82
Mean grade of Phil = 78.
Mean absolute deviation of Sidney = 3.28
Mean absolute deviation of Phil = 3.96.
The difference between the two means of Sidney and Phil = 82 - 78 = 4.
Thus, the ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28
Complete Question is;
The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below. Means and Mean Absolute Deviations of Sidney’s and Phil’s Grades Sidney Phil Mean 82 78 Mean Absolute Deviation 3.28 3.96 Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?
Read more about Mean Absolute Deviation at; brainly.com/question/447169
#SPJ1
Answer:
118 yards
Step-by-step explanation:
Tamia is getting balloons for her father's birthday party
She wants each balloon to be 6 feet long
Tamia wants to get 59 balloons
Therefore the yards of string needed can be calculated as follows
= 59×6
= 354 feet to yards
= 118 yards
Hence the number of yards needed is 118 yards
Answer:
Rounded Answer: 0
Not Rounded Answer: -0.00198019802
Step-by-step explanation:
Rounded Answer:
20/101 = 0.19801980198
Round that to 0.2
20/99 = 0.2
0.2-0.2 = 0
Not Rounded Answer:
20/101 = 0.19801980198
20/99 = 0.2
Answer: -0.00198019802
Answer:
16.25=1.75x
Step-by-step explanation:
so write it like this to that the bigger number(16.25) is on the left then write the other number(1.75)then put the X by the 1.75
Answer:
Given:
In Rhombus QRST, diagonals QS and RT intersect at W and U∈QR and point V∈RT such that UV⊥QR. (shown in below diagram)
To prove: QW•UR =WT•UV
Proof:
In a rhombus diagonals bisect perpendicularly,
Thus, in QRST
QW≅WS, WR ≅ WT and m∠QWR=m∠QWT=m∠RWS=m∠TWS=90°.
In triangles QWR and UVR,
(Right angles)
(Common angles)
By AA similarity postulate,
The corresponding sides in similar triangles are in same proportion,
(∵ WR ≅ WT )
Hence, proved.
