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3 years ago

Need help with 23. please

Mathematics

1 answer:

Masja [62]3 years ago

6 0

Val is at 200 Yards when Johnny stops for his friends.

You can see that because, at the same time (The Y-axis) that Johnny stops, Val is just at 200 yards

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Please help! I’ll give brainliest to the correct answer

ikadub [295]

Answer:

x = 7

Step-by-step explanation:

1*2*3*4*5*6*7 = 5040

x*8*9*10 = 720x

720x = 5040

720 / 5040 = 7

x = 7.

8 0

3 years ago

2+2 I need help with this, please

Vinvika [58]

Answer:

Step-by-step explanation:

2 cookies + 2 cookies = 4 cookies!

The more cookies the better!

4 0

3 years ago

Read 2 more answers

Math problem<br>6=2(y+2)<br>solve for y<br>y=?

kolbaska11 [484]

Answer:

y = 1

Step-by-step explanation:

2 (y + 2) = 6

2y + 4 = 6

2y = 6 - 4

2y = 2

y = 2/2

y = 1

5 0

3 years ago

Which triangle is similar to an equilateral triangle with perimeter 60 ft? Select one: any triangle with perimeter 60 feet an is

raketka [301]

an equilateral triangle with perimeter 7ft

4 0

3 years ago

In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag

Mashcka [7]

Answer:

The correct answer is D. 0.77

Step-by-step explanation:

$X_i \text{ is the difference between true and reported age. where i = 1,2,3......48 }\\\text{The rounded age are uniformly distributed. So, }X_i = 0\\\\and,\thinspace O_{X_i}^2=\frac{\text{(Upper Bound - Lower Bound})^2}{5\times 2.5\text{ ( Rounded value )}}\\\\O_{X_i}^2=\frac{(2.5 + 2.5)^2}{12}\approx 2.083\\\\O_X_i=1.443$

$\bar{X_{48}}=\frac{X_1+X_2+.......+X_{48}}{48}\\\\\bar{X_{48}}=\frac{\frac{48}{X_i}}{48}=0\\\\O_{\bar{X}_{48}}^2=\frac{48\cdot O_{X_i}^2}{48^2}=\frac{O_{X_i}^2}{48}\\\\\text{So, }\bar{X_i}\text{is approximately normal with mean 0 and standard deviation = }\\\\\frac{1.443}{\sqrt{48}}\approx 0.2083$

$=Pr[\frac{-1}{4}\leq \bar{X}_{48}\leq \frac{1}{4}]\\\\=Pr[\frac{-0.25}{0.2083}\leq Z\leq \frac{0.25}{0.2083}]\\\\=Pr[-1.2\leq Z\leq 1.2]\\=Pr(Z\leq 1.2)-Pr(Z\leq -1.2)\\=Pr(Z\leq 1.2)-(1-Pr(Z\leq 1.2))\\=2\times 0.8849 -1\text{ ( Z value for 1.2 is 0.8849 )}\\\approx 0.77$

Hence, the correct answer is 0.77

7 0

3 years ago