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mylen [45]
3 years ago
14

Suppose a 15 to 18-year-old male from Chile was 176 cm tall from 2009 to 2010. The z-score when x = 176 cm is z = _______. This

z-score tells you that x = 176 cm is ________ standard deviations to the ________ (right or left) of the mean _____ (What is the mean?)
Business
1 answer:
Nataly [62]3 years ago
5 0

Answer:

z = 0.96, standard deviations to the right of the mean 170 cm

Explanation:

z= \frac{176 - 170}{0.96}

x = 176 cm is 0.96, standard deviations to the right of the mean 170 cm

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Steve introduces in-house technical training programs for employees, as well as a provision to reimburse the tuition fees for em
Feliz [49]

Answer:

B. High performances work practice

Explanation:

High performance work practices are actions that tend to improve an organization's or a company's effectiveness and efficiency. They are practices structured to promote employees knowledge, improve commitment and motivate them. It involves investing in human power aimed at developing necessary skills, knowledge, techniques, and so on. In this scenario, Steve is trying to motivate and retain members of his organization by carry out high performance work practices like inhouse technical training and reimbursing tuition fees for employees who take relevant college courses.

5 0
3 years ago
Read 2 more answers
For 2019, Ashley has gross income of $38,350 and a $5,000 long-term capital loss. She claims the standard deduction of $18,350 a
kogti [31]

Answer:

carryover to 2020  = $2000

Explanation:

given data

gross income = $38,350

long-term capital loss = $5,000

standard deduction = $18,350

age = 35 years old

dependent = 2 children

to find out

How much of Ashley $5,000 capital loss carries over to 2020

solution

we know that here for the individual maximum capital loss deduction is

maximum capital loss deduction  = $3000 for household

so that carryover to 2020 will be here

carryover to 2020 = 5000 - 3000 = $2000

5 0
3 years ago
Bonnie purchased a new business asset (five-year property) on March 10, 2019, at a cost of $30,000. She also purchased a new bus
bearhunter [10]

Answer:  The cost recovery deduction for 2019 for these assets is $43000.

Explanation:

New business asset (five year property) purchased March 10, 2019 = $30000

New business asset (seven year property) purchased on November 20, 2019 = $13000

Additional depreciation of the first year is referred as the bonus depreciation.

Also, bonus depreciation in the year 2019 is at 100% of the value of assets bought during this year.

∴ Total assets value = New business asset (five year property) + New business asset (seven year property)

= $30000 + $13000

= $43000

Hence, the cost recovery deduction for 2019 for these assets is $43000.

6 0
3 years ago
An intangible asset with an estimated useful life of 30 years was acquired on January 1, 2007, for $540,000. On January 1, 2017,
algol [13]

Answer:

Amortization for the year 2017 is $12,000

Explanation:

Given:

Estimated Useful life = 30 years

Cost of Assets on January 1, 2007 = $540,000

Now,

The Amortization per year = \frac{\textup{Cost of asset}}{\textup{Useful life}}

or

The Amortization per year = \frac{\textup{540,000}}{\textup{30}}

or

The Amortization per year = $18,000

Thus,

Accumulated amortization on January 1, 2017

= Amortization per year 18000 × Number of years from 2007 to 2017

= $18,000 × 10

= $180,000

Therefore,

The Book Value of Asset on January 1, 2017 = $540,000 - $180,000

= $360,000

also,

The Revised useful life = 30 years

Therefore,

The Amortization per year = \frac{\textup{Current book value of asset}}{\textup{Useful life}}

or

The Amortization per year = \frac{\textup{360,000}}{\textup{30}}

or

The Amortization per year = $12,000

Hence,

Amortization for the year 2017 is $12,000

5 0
3 years ago
You have collected data on the number of U.S. households actively using online banking and/or online bill payment from 1995 to 2
MAXImum [283]

Answer:

D

Explanation:

time-series plot is a data visualization graph that illustrates data points at successive intervals or time.

6 0
4 years ago
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