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forsale [732]
3 years ago
8

Write your own two equations that would have a solution of (3, 6).

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

y = 2x

y = 3x - 3

Step-by-step explanation:

Hi,

<u>y = 2x</u>

<u>6 = 2(3)</u>

<u>6 = 6</u>

<u>That's a solution</u>

<u>y = 3x - 3</u>

<u>6 = 3(3) - 3</u>

<u>6 = 9 - 3</u>

<u>6 = 6</u>

<u>That's a solution</u>

Hope this helps :)

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-3p-9=6<br> Solve equation for p then justify your reasoning
fredd [130]
-3p-9=6
-3p=6+9
-3p=15
p=-5
6 0
3 years ago
Read 2 more answers
B=(2x+3)(4x^2-6x+9)-2(4^3-1)
nexus9112 [7]
B = (2x+3)(4x^2-6x+9)-2(4^3-1)
B = 8x^3-99

Hope it helps : )
5 0
1 year ago
Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward
bazaltina [42]

The graph of the function f(x) is

  • concave upward, when f''(x)>0;
  • concave downward, when f''(x)

Find f''(x):

1.

f'(x)=(x-4\cos x)'=1+4\sin x;

2.

f''(x)=4\cos x.

Now:

1. when 4\cos x>0, the graph of the function is concave upward and this is for

x\in \left(-\dfrac{\pi}{2}+2\pi k,\dfrac{\pi}{2}+2\pi k\right), \text{ where } k\in Z.

2.  when 4\cos x the graph of the function is concave downward and this is for

x\in \left(\dfrac{\pi}{2}+2\pi k,\dfrac{3\pi}{2}+2\pi k\right), \text{ where } k\in Z.

6 0
3 years ago
ANSWERRRRR PLEASE!! ~~
olganol [36]

Answer:

.33 liters of water and 3 liters of flour

Step-by-step explanation:

Well you can see how 1 liter of water is 3 liters of flour since there's a point on the graph, and you can find the liters of flour by just doing 1/3

8 0
3 years ago
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HELPPPPP PLEASEEEE!! ASAP please and thank you!
storchak [24]
To solve this problem we can find the area of the whole rectangle, then find the area of the smaller white rectangle inside the whole rectangle. Lastly, we can subtract the area of the smaller rectangle from the area of the whole rectangle which leaves us with the area of the shaded region.

Area of whole rectangle = length x width
= (3x + 6) (2x + 4)
= 6x squared + 24x + 24

Area of small rectangle = length x width
= (x-3) (x - 1)
= x squared - 4x + 3

Area of shaded region = area of whole rectangle - area of small rectangle
= 6x squared + 24x + 24 - x squared + 4x - 3
= 5x squared + 28x + 21
4 0
3 years ago
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