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3 years ago

Answer all & show work! WILL MARK BRAINLIEST!

Mathematics

1 answer:

Eddi Din [679]3 years ago

6 0

Answer:

Step-by-step explanation:

1 12

2 19

3 10

4 28

5 2

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The width of a rectangle is 2 cm less than 8 times the length. The perimeter is 68 cm. What are the width and length of the rect

eduard

Answer:

length=4

width=30

Step-by-step explanation:

length=x

width=8x-2

(8x-2)*2+2x=68

16x-4+2x=68

18x=72

x=4 (Length)

4*8=32, 32-2=30(width)

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3 years ago

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A relation is a function if _____.

valentina_108 [34]

... <span>exactly one output for each input

This is an important concept; be certain that you understand it.

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3 years ago

The perimeter of a rectangular garden is 40 it. The length is 2 ft more than the width. Find the length and the width of the gar

alexgriva [62]

Answer: Length = 11

Width = 9

Step-by-step explanation:

Let x represent the unknown length.

Let x - 2 represent the unknown width.

The perimeter is equal to 2 times x + (x -2)

Equation:

2 (x + (x - 2)) = 40

x + (x - 2) = 40/2

x + x - 2 = 20

2x - 2 = 20

2x -2 + 2 = 20 + 2

The length is: 2x = 22 -> x = 22/2 -> x = 11

The width is: x - 2 = 9

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3 years ago

a drink is made by mixing pineapple juice orange juice and lime juice in the ratio 2:7:3 Sally makes 600ml of the fruit drink ho

satela [25.4K]

Pineapple juice : orange juice : lime juice = 2:7:3
So there is 2x of pineapple juice, 7x of orange juice and 3x of lime juice.

$2x+7x+3x=600 \\
12x=600 \\
x=50 \\ \\
pineapple \ juice \to 2x = 2 \times 50=100$

She used 100 ml of pineapple juice.

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3 years ago

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Find the quadratic function that fits the following data. which one function fits.

Oksana_A [137]

Answer:

Step-by-step explanation:

The general rule for the quadratic function is

$y=ax^2+bx+c$

Use the data from the table:

$y(50)=130\Rightarrow 130=a\cdot 50^2+b\cdot 50+c\\ \\y(70)=130\Rightarrow 130=a\cdot 70^2+b\cdot 70+c\\ \\y(90)=200\Rightarrow 200=a\cdot 90^2+b\cdot 90+c$

We get the system of three equations:

$\left\{\begin{array}{l}2500a+50b+c=130\\ \\4900a+70b+c=130\\ \\8100a+90b+c=200\end{array}\right.$

Subtract these equations:

$\left\{\begin{array}{l}4900a+70b+c-2500a-50b-c=130-130\\ \\8100a+90b+c-2500a-50b-c=200-130\end{array}\right.\Rightarrow \left\{\begin{array}{l}2400a+20b=0\\ \\5600a+40b=70\end{array}\right.$