The amount of the radioactive substance is 374.6 g
<h3>How to determine the amount of
radioactive substance?</h3>
The given parameters are:
- Initial, a = 424 mg
- Rate, r = 6%
- Time, t = 2 hours
The amount of the radioactive substance is calculated as:
A(t) = a(1 - r)^t
This gives
A(t) = 424 * (1 - 6%)^t
At 2 hours, we have:
A(2) = 424 * (1 - 6%)^2
Evaluate
A(2) = 374.6
Hence, the amount of the radioactive substance is 374.6 g
Read more about exponential functions at:
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Answer:
y=1/4x+3
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(6-2)/(12-(-4))=4/(12+4)=4/16=1/4
y-y1=m(x-x1)
y-2=1/4(x-(-4))
y-2=1/4(x+4)
y=1/4x+4/4+2
y=1/4x+1+2
y=1/4x+3
Answer:
40
Step-by-step explanation:
Add all the sides together which is 40
<span>the dimensions of a door are variable, for effects of this problem we will assume a door height of 210 cm and a door width of 80 cm
Step 1
</span><span>convert the dimensions of the door in cm to inches
</span>we know that
1 in-------------> 2.54 cm
X----------------> 210 cm
X=210/2.54=82.67 in (height)
1 in-------------> 2.54 cm
X----------------> 80 cm
X=80/2.54=31.50 in (width)
the dimensions of a door are 31.50 in x 82.67 in
Step 2
calculate the amount of rules of 12-inches necessary to measure the height of the door
82.67 in (height)
if one rule-------------> measure 12 in
X----------------------> 82.67 in
X=82.67/12=6.8-----------> 7 rules
Step 3
calculate the amount of rules of 12-inches necessary to measure the width of the door
31.50 in (width)
if one rule-------------> measure 12 in
X----------------------> 31.50 in
X=31.50/12=6.8-----------> 2.62 ------------> 3 rules
the answer is
to measure a door are needed about 7 rules of 12-inches for the height and about 3 rules of 12-inches for the width
