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Vedmedyk [2.9K]
2 years ago
10

What the solution to -2y = 4x + 8

Mathematics
2 answers:
Kisachek [45]2 years ago
8 0

Answer:

4x 8

Step-by-step explanation:

4 x − 8 = 8 4x-8=8 4x−8=8. Add 8 to both sides. Simplify 8+8 8+8 8+8 to 16 16 16. Divide both sides by 4.

Elden [556K]2 years ago
8 0

Answer:

4x 8

Step-by-step explanation:

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kompoz [17]
Just divide 18 by 20 , so its 0.9
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2 years ago
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Sheila has x 20 dollar bills, and Tamsin has y 10 dollar bills. Sheila has a total of $50 more than Tamsin, but Tamsin has 1 mor
natka813 [3]

Answer:

Sheila have 6 bills

Step-by-step explanation:

Suppose Sheila has x '20' dollar bills, so the total cost of her bill = $20x

Suppose Tamsin has y '10' dollar bills, so the total cost of her bill = $10y

<h3>Equation 1</h3>

<em>Sheila has a total of $50 more than Tamsin</em>

<h2><em>10y + 50 = 20x</em></h2><h2 /><h3>Equation 2</h3>

<em>Tamsin has 1 more bill than Sheila.</em>

<h2>y = x + 1 </h2><h2 />

<em>Now solve them by putting value of x in equation </em>

10( x + 1 ) + 50 = 20x

10x + 10 + 50 = 20x

60 = 20x - 10x

10x = 60

x = 60/10

x = 6

and

y = 7

<em> </em>

6 0
3 years ago
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Yakvenalex [24]

Answer:

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Step-by-step explanation:

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3 years ago
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If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.
nydimaria [60]

Answer:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

Step-by-step explanation:

Given

\cos(\theta) = -\frac{2}{3}

\theta \to Quadrant III

Required

Determine \tan(\theta) \cdot \cot(\theta) + \csc(\theta)

We have:

\cos(\theta) = -\frac{2}{3}

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

\sin^2(\theta) + (-\frac{2}{3})^2 = 1

\sin^2(\theta) + (\frac{4}{9}) = 1

Collect like terms

\sin^2(\theta)  = 1 - \frac{4}{9}

Take LCM and solve

\sin^2(\theta)  = \frac{9 -4}{9}

\sin^2(\theta)  = \frac{5}{9}

Take the square roots of both sides

\sin(\theta)  = \±\frac{\sqrt 5}{3}

Sin is negative in quadrant III. So:

\sin(\theta)  = -\frac{\sqrt 5}{3}

Calculate \csc(\theta)

\csc(\theta) = \frac{1}{\sin(\theta)}

We have: \sin(\theta)  = -\frac{\sqrt 5}{3}

So:

\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}

\csc(\theta) = \frac{-3}{\sqrt 5}

Rationalize

\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}

\csc(\theta) = \frac{-3\sqrt 5}{5}

So, we have:

\tan(\theta) \cdot \cot(\theta) + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)

Substitute: \csc(\theta) = \frac{-3\sqrt 5}{5}

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}

Take LCM

\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}

6 0
3 years ago
What is the perimeter of the figure on the coordinate plane below?
erik [133]

Answer:

26 units

Step-by-step explanation:

im not sure if this will help but i counted the spaces and added the halves

3 0
3 years ago
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