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babunello [35]
3 years ago
7

What is the area of a triangle whose sides have length

7D%20%2C%20and%20%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " alt=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
atroni [7]3 years ago
6 0
The sides with square root of 70 would be 8.366600265340755. The side with the square root of 28 will be 5.291502622129181. 
Simplify the two square roots
square root of 70=8.36
square root of  28= 5.29

Use these simplified square roots and put them in with the formula and you should get your answer.
Hope this helps
Plz mark as brainlest :)
Thank you!
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GuDViN [60]
The supplement of < 72 has the same measure as < (4x + 8). Therefore, < (4x + 8) must equal 108°. We can establish the following equality statement to solve for x:

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Combine like terms:
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Subtract 80 from both sides:

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Divide both sides by 4 to solve for x:

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To verify whether the value of x is correct, substitute its value into the equality statement:

< (4x + 8)° + < 72° = 180°

< [4(25) + 8]° + < 72° = 180°

< (100 + 8)° + < 72° = 180°

< 108° + < 72° = 180°

180° = 180° (True statement. Therefore, the correct answer is x = 25).

Please mark my answers as the Brainliest if you find this helpful :)
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2 years ago
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olga2289 [7]

Hey there!

-1 ¼ • 9

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= -(5 × 9)/4

= <u>-</u><u> </u><u>4</u><u>5/4</u>

= <u>- 11.25</u>

Hope it helps ya!

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