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babunello [35]
3 years ago
7

What is the area of a triangle whose sides have length

7D%20%2C%20and%20%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " alt=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
atroni [7]3 years ago
6 0
The sides with square root of 70 would be 8.366600265340755. The side with the square root of 28 will be 5.291502622129181. 
Simplify the two square roots
square root of 70=8.36
square root of  28= 5.29

Use these simplified square roots and put them in with the formula and you should get your answer.
Hope this helps
Plz mark as brainlest :)
Thank you!
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Solve the equation of exponential decay.
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Answer:

$9,220,000(0.888)^t

Step-by-step explanation:

Model this using the following formula:

Value = (Present Value)*(1 - rate of decay)^(number of years)

Here, Value after t years = $9,220,000(1 -0.112)^t

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3 years ago
Find x and y in the figure​
Grace [21]

Answer:

x=10, y=25

Step-by-step explanation:

First, in a trapezoid, the two angles on the same leg (the legs are the opposite sides that are not parallel) add up to 180 degrees. Therefore, 4y as well as (2y+3x) are supplementary. We can write this out as

4y + (2y+3x) = 180

6y+3x = 180

Next, the angles of a triangle add up to 180 degrees. Therefore, as the angles 2y, 4y, and (5x-20) make up a triangle, they add up to 180 degrees. We can write this as

4y + 2y + (5x-20) = 180

6y + 5x -20  =180

Our two equations are thus

6y + 5x - 20 = 180

6y + 3x = 180

If we subtract 6y from both sides in each equation, we can say

5x - 20 = 180-6y

3x = 180-6y

Therefore, we can write

5x-20 = 180-5y = 3x

5x-20=3x

subtract 3x from both sides to make all x variables on the same side

2x-20 = 0

add 20 to both sides to isolate the x and its coefficient

2x = 20

divide both sides by 2 to isolate x

x = 10

Therefore,

x = 10

6y + 3x = 180

6y + 30 = 180

subtract 30 from both sides to isolate the y and its coefficient

6y = 150

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5 0
3 years ago
Is this a quadratic function 2x+13=13
lys-0071 [83]

Answer:

Step-by-step explanation:

Simplifying

2x + 13 = 0

Reorder the terms:

13 + 2x = 0

Solving

13 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.

13 + -13 + 2x = 0 + -13

Combine like terms: 13 + -13 = 0

0 + 2x = 0 + -13

2x = 0 + -13

Combine like terms: 0 + -13 = -13

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x = -6.5

7 0
2 years ago
Solve for x {x+4]= 6
wlad13 [49]

The solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.

<h3>What is a quadratic equation?</h3>

Any equation of the form \rm ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}

We have an equation:

x(x + 4) = 6

By distributive property:

x² + 4x = 6

x² + 4x - 6 = 0

a = 1, b = 4, c = -6

Plugging all the values in the formula:

\rm x = \dfrac{-4 \pm\sqrt{4^2-4(1)(-6)}}{2(1)}

After calculating:

\rm x = \dfrac{-4 \pm\sqrt{40}}{2}

\rm x=-2+\sqrt{10},\ \ \ or \ \ \ x=-2-\sqrt{10}

Thus, the solution to the equation x(x+4) = 6 is x = -2 + √10 or x = -2 - √10 after solving with the quadratic formula.

Learn more about quadratic equations here:

brainly.com/question/2263981

#SPJ1

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