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babunello [35]
3 years ago
7

What is the area of a triangle whose sides have length

7D%20%2C%20and%20%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " alt=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
atroni [7]3 years ago
6 0
The sides with square root of 70 would be 8.366600265340755. The side with the square root of 28 will be 5.291502622129181. 
Simplify the two square roots
square root of 70=8.36
square root of  28= 5.29

Use these simplified square roots and put them in with the formula and you should get your answer.
Hope this helps
Plz mark as brainlest :)
Thank you!
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6 0
3 years ago
The answers to this question cousin
podryga [215]
If R is between Q and S then QR+RS=QS

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QR=x+4
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