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babunello [35]
3 years ago
7

What is the area of a triangle whose sides have length

7D%20%2C%20and%20%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " alt=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
atroni [7]3 years ago
6 0
The sides with square root of 70 would be 8.366600265340755. The side with the square root of 28 will be 5.291502622129181. 
Simplify the two square roots
square root of 70=8.36
square root of  28= 5.29

Use these simplified square roots and put them in with the formula and you should get your answer.
Hope this helps
Plz mark as brainlest :)
Thank you!
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Answer:

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8 0
2 years ago
I’m having a lot of trouble, can someone guide me, step by step?
shutvik [7]

Answer:

Hi hopefully this helps you!

Step-by-step explanation:

To find the area of a circle you can use the formula A = πr^2

The radius of a circle is just the diameter divided by 2. In this case we know the diameter is 3, so the radius is 1.5

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Add up the area of this semi circle with the area of the rectangle

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To find the circumference/ perimeter of a circle use this formula C = 2πR

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Hope this helps! Best of luck in your studies <3

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