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babunello [35]
3 years ago
7

What is the area of a triangle whose sides have length

7D%20%2C%20and%20%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " alt=" \sqrt{70}, \sqrt{70} , and \sqrt{28} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
atroni [7]3 years ago
6 0
The sides with square root of 70 would be 8.366600265340755. The side with the square root of 28 will be 5.291502622129181. 
Simplify the two square roots
square root of 70=8.36
square root of  28= 5.29

Use these simplified square roots and put them in with the formula and you should get your answer.
Hope this helps
Plz mark as brainlest :)
Thank you!
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Need help ASAP
Margarita [4]
<span>Angle T = Angle C, let them equal x

So x + x + 140 = 180

2x = 40

x = 20

So Angle T = 20 degrees </span>
6 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
A man earns $3580 per month and spend 65% of it. How much does he save every month?
Sloan [31]

Answer:

23000 dollars

Step-by-step explanation: because 3580 is about i dont even know scrub

4 0
2 years ago
Solve the equation <br> y-x=17<br> y=4x+2
gogolik [260]
Y-x =17
y = -x + 17

substitute this into the second equation

y = 4x + 2
-x + 17 = 4x + 2
0= 5x -15
15/5 = 5x/5
3 = x
4 0
3 years ago
Is the graph increasing, decreasing, or constant where -3 &lt; X &lt;-1?
Romashka [77]

Answer:

decreasing

Step-by-step explanation:

since its negative it will slope down

8 0
3 years ago
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