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kolbaska11 [484]
3 years ago
15

If sin (x-3)° = cos (2x + 6)°, then what is the value of x? * 10 points

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0

Answer:

x= -9

Step-by-step explanation:

Sin is equal to cos.  x-3=2x+6 and you solve.

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PLEASE HELP ME QUICKKKK!
telo118 [61]

Look up what is mean and calculate it.

5 0
2 years ago
Select the equivalent expression.
Vanyuwa [196]

For this case we must find an expression equivalent to:(y ^ 3 * 2 ^ 5) ^ 2

By definition of power properties we have to meet:

(a ^ n) ^ m = a ^ {n * m}

So, rewriting the expression we have:

y^{3 * 2} * 2^ {5 * 2} =\\y^ 6 * 2^{10}

Answer:

Option B

y^6*2^{10}

4 0
3 years ago
D is the midpoint of RJ⎯⎯⎯⎯. R has coordinates (−4,7), and D has coordinates (2,−1). Identify the coordinates of J.
Aleksandr [31]

Answer:

(8,-9)

Step-by-step explanation:

If the x-coordinate of R is 6 units away from D's x-coordinate, then so will J's x-coordinate. If the y-coordinate of R is 8 units away from D's y-coordinate, then so will J's y-coordinate.

Side note/Extra information:

The line would be y=\frac{-4}{3} x+\frac{5}{3}

3 0
2 years ago
What equation can you write to solve for x?
KengaRu [80]

Answer:

(3x) ° + (x+ 10)° = 90°

Step-by-step explanation:

(3x) ° + (x+ 10)° = 90°

3x + x + 10 = 90

4x = 90 - 10

4x = 80

x = 20

(3x) ° = 3 x 20 = 60°

(x + 10)° = 20 + 10 = 30°

4 0
3 years ago
Read 2 more answers
Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i
Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em>  and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558

(b) What is the probability that at least 4 arrive during a 1-hour period?

\bf P(X\geq4)=1-P(X

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}

and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But

\bf P(X

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0
3 years ago
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