Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
I think it is .1324 but I need a little more details.
Answer:
C
Step-by-step explanation:
Answer:
It's below in the explanation
Explanation
1. x has to be greater than 2. So 3 and 4 both work
2. x has to be less than 22. So 21 and 20 both work
3. t has to be less than 5. So 3 and 4 both work
4. There isn't a number there. what is 5 less that?
5. j has to be less than 5 so 5 and 4 both work
6. y has to be less than 4. So 4 and 3 both work
7. B has to be greater than 26. so 26 27 and 28 all work
8.There isn't a number there
9.b can be 3 or greater than 3.
10.z can be 6 or greater than 6
Hope this Helps!
Answer:
C. 40 square inches but i could be wrong