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3 years ago

- 7x² + 2 + 12x – 14 - 10x?

Mathematics

2 answers:

Alisiya [41]3 years ago

6 0

I'm not sure what you're asking but if you're looking for simplification, here it is. -7x² + 2x - 12

Marrrta [24]3 years ago

4 0

Answer:

2x-61

Step-by-step explanation:

12x-10x-7^2+2-14

2x-7^2+2-14

2x-7^2-12

2x-49-12

2x-61

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On a vacation trip to Canada you realize that the speed limit signs are in km/hour. Unfortunately, your speedometer only reads i

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120 km is 74.56 miles so just round that

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There are 6 dogs and 12 cats in the backyard. Write the ratio of cats to total animals In 3 ways, in simplest form.

Luda [366]

Step-by-step explanation:

12:18

12 to 18

12/18 = 2/3

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3 years ago

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AfilCa [17]

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122.5 cm²

Step-by-step explanation:

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3 years ago

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Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

3 years ago

The average length of a ladybug can range from 0.08 to 0.4 inches. Find two lengths that are within the given span.Write them as

Alenkinab [10]

The average length of a ladybug can range from 0.08 to 0.4 inches.

So two lengths within the given span are 0.1 inch and 0.3 inches.

$In \: fraction: \\ \\ 0.1 \: inch = \frac{1}{10} \: inch \\ \\ 0.3 \: inch = \frac{3}{10} \: inch$

7 0

3 years ago